Can't update query with mysqli [duplicate] - php

Question

This question already has an answer here:
What to do with mysqli problems? Errors like mysqli_fetch_array(): Argument #1 must be of type mysqli_result and such
(1 answer)
Closed 6 years ago.
I checked source code ten times but can't find anymistake,for some reason i remember it was working now it doesn't work,i didn't change anything elsewhere to blame everything wors except update,when iclick Edit button it gives error,meaning that there was something wrong with query.
<?php
$editId = $_GET['id'];
$event = mysqli_query($con, "SELECT * FROM events WHERE id = '$editId'")->fetch_assoc();
if(isset($_POST['submit'])){
$name = $_POST['name'];
$description = $_POST['description'];
$date = $_POST['date'];
$artists = $_POST['artists'];
$tickets = $_POST['tickets'];
$updateQuery = mysqli_query($con, "UPDATE events SET name='$name',description='$description',date='$date', artists='$artists', ticket='$tickets' WHERE id = '$editId'");
}
?>
<?php if(isset($updateQuery) && $updateQuery): ?>
<div class="alert alert-success">
<strong>Successfully Edited</strong>
</div>
<?php endif; ?>
<?php if(isset($updateQuery) && !$updateQuery): ?>
<div class="alert alert-danger">
<strong>Error</strong>
</div>
<?php endif; ?>
<form action="<?php echo $app_host; ?>/admin/?page=editevent&id=<?php echo $editId; ?>" method="post">
<div class="form-group">
<label for="name">Name</label>
<input value="<?php echo $event['name']; ?>" required="true" type="text" class="form-control" id="name" name="name">
</div>
<div class="form-group">
<label for="description">Description</label>
<textarea class="form-control" id="description" name="description"><?php echo $event['description'];; ?></textarea>
</div>
<div class="form-group">
<label for="date">Date</label>
<input value="<?php echo $event['date']; ?>" required="true" type="text" class="form-control" id="date" name="date">
</div>
<div class="form-group">
<label for="artists">Artists</label>
<input value="<?php echo $event['artists']; ?>" required="true" type="text" class="form-control" id="artists" name="artists" data-role="tagsinput">
</div>
<div class="form-group">
<label for="tickets">Ticket Link</label>
<input value="<?php echo $event['tickets']; ?>" required="true" type="text" class="form-control" id="tickets" name="tickets" data-role="tagsinput">
</div>
<input name="submit" type="submit" class="btn btn-default" value="Edit Event" />
</form>

Answer 1

Okay,so you declare a variable ,
$tickets = $_POST['tickets'];
and than you say
$updateQuery = mysqli_query($con, "UPDATE events SET name='$name',description='$description',date='$date', artists='$artists', ticket='$tickets' WHERE id = '$editId'");
}
and solution is simple:
$updateQuery = mysqli_query($con, "UPDATE events SET name='$name',description='$description',date='$date', artists='$artists', tickets='$tickets' WHERE id = '$editId'");
}
simply changed 'ticket' in query to 'tickets'.