So I have this code for my Google pie chart (pie chart code not included, but it works fine and displays data)
<?php
$query = "SELECT * FROM category WHERE type = 'Expense' ";
$select_category_list = mysqli_query($connection, $query);
while($row = mysqli_fetch_assoc($select_category_list)) {
$cat_id = $row['id'];
$cat_title = $row['title'];
echo "['$cat_title'" . ",";
echo "$cat_id],";
}
?>
I put the echo in different lines, but it really does not matter to if they are in one line or in two lines, what matters is to get it finally working :)
Instead of $cat_id I want to put the SUM ($cat_amount) calculated by this code:
$query = "SELECT category_id, SUM(amount) AS TotalAmount FROM spendee
WHERE type = 'Expense' group by category_id ";
$expense_query = mysqli_query($connection, $query);
while ($row = mysqli_fetch_assoc($expense_query)) {
$cat_amount = $row['TotalAmount'];
}
I have tried putting while loop in a while loop, foreach loop in a while loop, putting $cat_amount instead of $cat_id (that only displays one SUM) and so on. Nothing worked. I have not tried the for loop, but I assume the result would be the same + I am not sure how would I define the times that the loop needs to run, since there could be many type 'Expense' categories added in time.
Any help would be very much appreciated. Thank you and have a lovely day.
maybe i'm missing something, but looks like you could join the two tables in one query
this would get the desired result in one query / loop...
sql:
SELECT a.title as Title, SUM(b.amount) AS TotalAmount FROM category a, spendee b WHERE b.category_id = a.id and b.type = 'Expense' group by a.title
php:
<?php
$query = "SELECT a.title as Title, SUM(b.amount) AS TotalAmount FROM category a, spendee b WHERE b.category_id = a.id and b.type = 'Expense' group by a.title";
$select_category_list = mysqli_query($connection, $query);
while ($row = mysqli_fetch_assoc($select_category_list)) {
$cat_title = $row['Title'];
$cat_amount = $row['TotalAmount'];
echo "['$cat_title'" . ",";
echo "$cat_amount],";
}
?>
Related
I'm starting to learn php. I'm able to extract the list of CD from the SQL query in [in this table][1] but there's another query which contains the Category which is linked via ID in this table.
How do I get all the columns in the same result set using one query?
<?php
include 'database_conn.php';
$sql = "SELECT id, title, year, price FROM table_cd";
$queryresult = mysqli_query($conn, $sql)
or die (mysqli_error($conn));
while($row = mysqli_fetch_assoc($queryresult)) {
$iid = $row['id'];
$title = $row['title'];
$year = $row['year'];
$price = $row['price'];
echo "<div>
$title
</div>\n";
echo $row['year'];
echo $row['price'];
}
?>
editCDForm.php:
<?php
$code = $_GET['itemCode'];
$sql = "SELECT * FROM table_cd WHERE table_category.ID = $code
JOIN table_category ON (table_category.Desc = table_cd.ID)";
?>
What you're looking for is called a JOIN which allows you to merge the rows from two or more tables into the same result set.
You can modify your query as illustrated below, by using a LEFT JOIN of the nmc_cd table and the nmc_category table on the catID column, as the common primary attribute between them, giving you the desired result set...
$sql = "SELECT nmc_cd.CDID, nmc_cd.CDTitle, nmc_cd.CDYear,
nmc_cd.CDPrice, nmc_category.catDesc
FROM nmc_cd
JOIN nmc_category on nmc_cd.catID = nmc_cd.catID";
Here's a nice article that may help you visualize what a JOIN looks like in your SQL.
Syntax for joins:
SELECT * FROM table1
JOIN table2 ON (table2.colunmname = table1.columnname)
use can get the data from both tables when joining them:
$sql = "SELECT FT.CDID, FT.CDTitle, FT.CDYear, FT.CDPrice,
ST.catDesc FROM nmc_cd AS FT LEFT JOIN nmc_category as ST ON
FT.catID=ST.catID";
I'm trying to display a list of status updates from artists that a logged in user is following.
So far I have this:
#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
#Now grab the statuses for each artist
$status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
$status_result = mysqli_query($dbc,$status_query)
}
But i'm not sure how to loop through and display the returned status updates?
This isn't a strong point of mine, so any pointers would be greatly appreciated!
What prevented you from doing similar to what you'd already done for the first query? Something like follows:
#Get the list of artists that the user has liked
$q = "SELECT * FROM artist_likes WHERE user_id = '1' ";
$r = mysqli_query($dbc,$q);
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
#Now grab the statuses for each artist
$status_query = "SELECT * FROM status_updates WHERE artist_id = '".$row['artist_id']."' ";
$status_result = mysqli_query($dbc,$status_query)
while($status_result_row = mysqli_fetch_assoc($status_result)) {
echo $status_result_row['mycol']; // This is where you know better than us
}
}
Or if those two tables artist_likes and status_updates have artist_id in common then you could just use one query with a join. (But don't know if you are asking for that).
Just for avoiding multiple query, you can use one query like this:
SELECT l.*, s.*
from artist_likes l, status_updates s
WHERE
l.artist_id = s.artist_id and
l.user_id = '1'
or
SELECT l.*, s.*
from artist_likes l
JOIN status_updates s on (l.artist_id = s.artist_id)
WHERE
l.user_id = '1'
I currently have this query with an array that outputs the variables within using a dynamic input in my form (term), this creates a Dynamic Search with auto complete to fill in all of the details for a product.
$return_arr = array();
$param = $_GET["term"];
$fetch = mysql_query("SELECT * FROM crd_jshopping_products WHERE `name_en-GB` REGEXP '^$param'");
while ($row = mysql_fetch_array($fetch, MYSQL_ASSOC)) {
//$row_array['category_id'] = $row ['category_id'];
$row_array['product_id'] = $row['product_id'];
$row_array['product_names'] = $row['name_en-GB'];
$row_array['jshop_code_prod'] = $row['product_ean'];
$row_array['_ext_price_html'] = number_format($row['product_price'],2);
if (!empty($row['product_thumb_image']) AND isset($row['product_thumb_image'])){
$row_array['image'] = $row['product_thumb_image'];
}else {
$row_array['image'] = 'noimage.gif';
}
array_push( $return_arr, $row_array);
}
mysql_close($conn);
echo json_encode($return_arr);
Unfortunately I also need to get the category_id which is not in the same table, I have tried to modify my query as such, but to no avail:
$fetch = mysql_query("SELECT * FROM crd_jshopping_products WHERE `name_en-GB` REGEXP '^$param' AND `crd_jshopping_products_to_categories` = `product_id` ");
What step am I missing here ? The product_id's match in both tables?
try this query instead and try to understand what I have written in it:
$fetch = mysql_query("
SELECT
p.*,
c.category_id
FROM
crd_jshopping_products as p
INNER JOIN crd_jshopping_products_to_categories as c
ON p.product_id = c.product_id
WHERE
`p.name_en-GB` REGEXP '^$param'
");
This means:
SELECT:
Give me everything from p and the category_id from c.
FROM:
Do this from rows in the tables crd_jshopping_products (referred to as p) and crd_jshopping_products_to_categories (referred to as c), where the rows match on the count of p.product_id is the same as c.product_id.
WHERE:
Only return the rows where p.name_en-GB REGEXP '^$param'.
I have a table categories that has: id, name, subcategory_id, parent_id. Another table classifieds that has: classified_id, title, description, category_id.
I am trying to to pull numbers of classifieds in each category. So it will look like this.
Accessories(10)
Cars(15)
Dating(12)
I gave it a try like this:
enter $catquery = mysql_query("SELECT * FROM categories WHERE sub_id = '0' ORDER BY name ASC"); here
enter $catrows = mysql_num_rows($catquery); here
enter $catrows = mysql_num_rows($catquery); here
enter $query = "SELECT category_id, COUNT(title) AS `total` FROM classifieds WHERE classified_id = 'category_id' "; here
enter $result = mysql_query($query); here
enter while($row = mysql_fetch_assoc($result)){ $num_items_in_category[$row['category_id']] = $row['total']; here
enter } echo "<li><a href='category.php?cat=".$row['id']."'>".$row['name']. $row['total']. "</a></li>"; here
Thanks fellas
You should be able to accomplish what you're looking for by joining the 2 tables.
SELECT a.name, count(*) as cnt
FROM categories a
join classifieds b
on a.id = b.category_id
group by a.name
COUNT is an aggregate function, so you can get all of the counts at once.
I believe what you are looking for is
$query = "SELECT category-id, COUNT(title) AS `total` FROM classifieds WHERE classified-id = 'category-cat' GROUP BY category-id";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result)){
$num_items_in_category[$row['category-id']] = $row['total'];
}
This will give you associative array with the count of records for each category-id
I have a very simple query but I need to make another query inside it. I have very little knowledge of SQL and PHP so I want to ask your help.
$result = mysql_query("SELECT * FROM img");
while ($row = mysql_fetch_assoc($result))
{
$imgName = $row['name'];
$catID = $row['catid'];
// Problem
// Need to get category NAME from category ID
$result2 = mysql_query("SELECT name FROM cat WHERE id = $catID");
while ($row2 = mysql_fetch_assoc($result2))
{
$catName = $row2['name'];
}
echo "Image: $imgName <br />";
echo "Category: $catName";
}
This looks to be a simple JOIN to get the category name. You can use a single query:
SELECT
img.id AS imgId,
img.name AS imgName,
cat.name AS catName
FROM img JOIN cat ON img.catid = cat.id
Replace your initial query with the above, and it will eliminate the need for the inner query.
You could do a simple subquery on this one:
$result = mysql_query("
SELECT name, catid, (SELECT name FROM cat WHERE id = img.catid) AS cat_name
FROM img
");
This should work. You'll see all the img properties of each table in each row and in addition the cat.name value.
SELECT *, cat.name as catname FROM img
INNER JOIN cat
ON cat.id = img.catid