How does one pass the properties of a $_POST to a Function? - php

Question

I would like to pass the properties to a function to Update details in a database. I want all the columns that were selected in the form to be passed to a function. Frankly, I don't know what to do.
My code is the following:
if (isset($_POST["updateWineButton"])) {
$wineID = $_POST["wineID"];
$wineCountryID = $_POST["wineCountryID"];
$wineSizeID = $_POST["wineSizeID"];
$wineRatingID = $_POST["wineRatingID"];
$wineColourID = $_POST["wineColourID"];
$packageID = $_POST["packageID"];
$wineCategoryID = $_POST["wineCategoryID"];
$wineCode = $_POST["wineCode"];
$price = $_POST["price"];
$description = $_POST["description"];
$wineRating = $_POST["wineRating"];
$wineIMG = $_POST["wineIMG"];
updateWine($updateWine);
$status = "$description has been updated.";
}
Update Wine Function
function updateWine($wineUpdate)
{
global $pdo;
$statement = $pdo->prepare("UPDATE WINE SET wineID=?, wineCountryID=?, wineSizeID=?, wineRatingID, wineColourID=?,
packageID=?, wineCategoryID=?, wineCode=?, price=?, description=?, wineRating=?, wineIMG=?
WHERE wineID=?");
$statement->execute([$wineUpdate->wineID,
$wineUpdate->wineCountryID,
$wineUpdate->wineSizeID,
$wineUpdate->wineRatingID,
$wineUpdate->wineColourID,
$wineUpdate->packageID,
$wineUpdate->wineCategoryID,
$wineUpdate->wineCode,
$wineUpdate->price,
$wineUpdate->description,
$wineUpdate->wineRatingID,
$wineUpdate->wineIMG]);
$statement->fetch();
}

Answer 1

Something like the following should work for you:
function updateWine()
{
global $pdo;
$keys = [
"wineID", "wineCountryID", "wineSizeID", "wineRatingID", "wineColourID", "packageID", "wineCategoryID",
"wineCode", "price", "description", "wineRating", "wineIMG",
];
$results = [];
foreach ($keys as $index) {
if (isset($_POST[$index])) {
$results[$index] = $_POST[$index];
}
}
$statement = $pdo->prepare("UPDATE WINE SET " . implode('=?, ', array_keys($results)) . "=? WHERE wineID =?");
$statement->execute(array_merge(array_values($results), [$_POST['wineID']]));
$statement->fetch();
}
if (isset($_POST["updateWineButton"]) && isset($_POST['wineID'])) {
updateWine();
}
Hope this helps!

Answer 2

if I understand correctly you want to do something like this,
if (isset($_POST["updateWineButton"])) {
$result = updateWine($_POST);
if($result){
$status = "$description has been updated.";
}else{
$status = "An error occurred.";
}
}
//your function woud then look like ...
function updateWine($postdata){
$wineID = $postdata["wineID"];
$wineCountryID = $postdata["wineCountryID"];
$wineSizeID = $postdata["wineSizeID"];
$wineRatingID = $postdata["wineRatingID"];
$wineColourID = $postdata["wineColourID"];
$packageID = $postdata["packageID"];
$wineCategoryID = $postdata["wineCategoryID"];
$wineCode = $postdata["wineCode"];
$price = $postdata["price"];
$description = $postdata["description"];
$wineRating = $postdata["wineRating"];
$wineIMG = $postdata["wineIMG"];
//udpate your database with the above values
//check if update is successful
return true;
//else if there was an error
return false;
}