how to give a unique variable name for each result? - php

Question

I want to give each output a unique variable name so I can use it anyway I want Any help?
<?php
$sql = "SELECT * FROM db";
$result = mysqli_query($con, $sql);
while($row= mysqli_fetch_assoc($result)) {
$var = $row['field_name'];
echo $var."<br>";
// Outputs name1 name2 etc.,
}
?>

Answer 1

<?php
$sql = "SELECT * FROM db";
$result = mysqli_query($con, $sql);
$var = array();
while($row= mysqli_fetch_assoc($result)) {
$var['name1'] = $row['field_name_1'];
$var['name2'] = $row['field_name_2'];
}
echo $var['name1']." ".$var['name2'];
?>
Is this what you are looking for?

Answer 2

You'll want to store them in an array, unless you want to go to the trouble of creating dynamic variable names.
<?php
$names = array();
$sql = "SELECT * FROM db";
$result = mysqli_query($con, $sql);
while($row= mysqli_fetch_assoc($result)) {
$var = $row['field_name'];
echo $var."<br>";
// Outputs name1 name2 etc.,
$names[] = $var;
}
echo $names[0];
echo $names[1];
// etc.

Answer 3

As Sahil said in comments extract() is a good option.
extract($row)
$row is an associative array. This function treats keys as variable names and values as variable values.For each key/value pair it will create a variable in the current symbol table
Read more about extract() here
<?php
$sql = "SELECT * FROM db";
$result = mysqli_query($con, $sql);
while($row= mysqli_fetch_assoc($result)) {
extract($row);
//now you can echo each value using its field name
echo $fieldname1;
echo $fieldname2;
}
?>