Why is my json data not being INSERTed into mySQL database? - php

Question

I created a PHP handler to receive a JSON payload from a POST request and then insert it into a database in phpMyAdmin. I'm not sure why this is not working.
JSON:
payload = {
"version":"1.0",
"event":"video_recorded",
"data":{
"videoName":"vs1457013120534_862",
"audioCodec":"NellyMoser ASAO",
"videoCodec":"H.264",
"type":"FLV",
"orientation":"landscape",
"id":"0",
"dateTime":"2016-03-03 15:51:44",
"timeZone":"Europe/Bucharest",
"payload":"111.111.111.11",
"httpReferer":"http://site_from_where_video_was_recorded.com"
}
}
The PHP code I got from a tutorial online. The tutorial was from 2017 so I'm assuming everything is up to date, but yet it still does not work:
<?php
/* db variables */
$dbhost = 'localhost';
$dbname = 'name_db';
$dbuser = 'user_db';
$dbpass = 'pass_db';
/* grab the json */
$data = $_POST['payload'];
/* put json into php associative array */
$data_array = json_decode($data);
/* store in PHP variables */
$ip_address = $data_array['data']['payload'];
$vid_name = $data_array['data']['videoName'];
$date_time = $data_array['data']['dateTime'];
$time_zone = $data_array['data']['timeZone'];
/* connect to mysql db */
$con = mysql_connect($dbuser, $dbpass, $dbhost) or die('Could not connect: ' . mysql_error());
/* select the specific db */
mysql_select_db($dbname, $con);
/* insert the values into the db */
$sql = "INSERT INTO ip_and_videos(IpAddress, VideoName, DateTime, Timezone) VALUES('$ip_address','$vid_name','$date_time','$time_zone')";
if(!mysql_query($sql,$con))
{
die('Error : ' . mysql_error());
}
?>
I have the primary key set to an int and have it on auto increment. If I understand correctly I don't need to insert anything into that column because it will assign a number each time. Or do I still need to pass it when I INSERT the other variables?

Answer 1

This works for the array part, you get correct answer. So, your code is not bad, but you should check all errors (as stated by Bhavin in comment). And I'm retty sure you have a typo -> $vid_name = $data_array['data']['videName']; is NOT like $vid_name = $data_array['data']['videoName']; Thereforer, error_reporting will be very helpful, and after that, check the query if other errors (prepared statements ^^)
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$payload = '{
"version":"1.0",
"event":"video_recorded",
"data": {
"videoName":"vs1457013120534_862",
"audioCodec":"NellyMoser ASAO",
"videoCodec":"H.264",
"type":"FLV",
"orientation":"landscape",
"id":"0",
"dateTime":"2016-03-03 15:51:44",
"timeZone":"Europe/Bucharest",
"payload":"111.111.111.11",
"httpReferer":"http://site_from_where_video_was_recorded.com"
}
}';
$data_array = json_decode($payload, true);
/* store in PHP variables */
$ip_address = $data_array['data']['payload'];
$vid_name = $data_array['data']['videoName'];
$date_time = $data_array['data']['dateTime'];
$time_zone = $data_array['data']['timeZone'];
echo"[ $ip_address / $vid_name / $date_time / $time_zone ]";
// EDIT : added query
include"config.inc.php";
// connect to DB
$mysqli = mysqli_connect("$host", "$user", "$mdp", "$db");
if (mysqli_connect_errno()) { echo "Error connecting : " . mysqli_connect_error($mysqli); }
$query = " INSERT INTO ip_and_videos (`IpAddress`, `VideoName`, `DateTime`, `Timezone`) VALUES (?,?,?,?) ";
$stmt = $mysqli->prepare($query);
print_r($stmt->error_list);
$stmt->bind_param("ssss", $ip_address, $vid_name, $date_time, $time_zone );
if (!$stmt->execute()) { echo $stmt->error; } else { echo"true"; }
?>

Answer 2

Not sure if you had the same issue but this does not work for me...
$vid_name = $data_array['data']['videName'];
I had to use
$vid_name = $data_array->data->videoName;
Can't use stdClass as an array.

Answer 3

Should be better this way
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
/* db variables */
$dbhost = 'localhost';
$dbname = 'name_db';
$dbuser = 'user_db';
$dbpass = 'pass_db';
/* grab the json */
$data = $_POST['payload'];
/* put json into php associative array */
$alldata = json_decode($data,true);
print_r($alldata);
/* connect to mysql db */
$con = mysql_connect($dbuser, $dbpass, $dbhost) or die('Could not connect: ' . mysql_error());
/* select the specific db */
mysql_select_db($dbname, $con);
/* insert the values into the db */
foreach($alldata as $data_array) {
$ip_address = $data_array['data']['payload'];
$vid_name = $data_array['data']['videoName'];
$date_time = $data_array['data']['dateTime'];
$time_zone = $data_array['data']['timeZone'];
$sql = "INSERT INTO ip_and_videos(IpAddress, VideoName, DateTime, Timezone) VALUES('".$ip_address."','".$vid_name."','".$date_time."','".$time_zone."')";
mysql_query($sql);
echo mysql_errno($con) . ": " . mysql_error($con) . "\n";
}
?>
Hope this helps