Printing out each row from a MYSQL table individually in PHP - php

Question

I am trying to individually print out each line from my SQL database in PHP. I am trying to do this so each line that is retrieved, it can act like a link which will direct the user to another page. For example, the current SQL query will output the Category names from the database Category, i would like it to output all the values from that table but have it so each one has a different redirect link to another page which clicked on.
$query = "SELECT CATEGORY_NAME
FROM CATEGORIES ORDER BY CATEGORY_ID ASC";
$results = #mysqli_query ($conn, $query);
$numrows = mysqli_num_rows($results);
if ($results) {
if ($numrows >0) {
echo '
<table>
<tr>
<td><strong>Categories</stong></td>
</tr>';
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)) {
echo '<tr>
<td>' . $row['CATEGORY_NAME'] . '</td>
</tr>
';
}
mysqli_free_result ($results);
Such as,
Category
__________
PS4
XBOX
i can click on PS4 and it would take me to another page, i know how to do this with a href and then print out the row in sql however, i'm not sure how do print out each row individually without printing them out using $row['CATEGORY_NAME'].
Thank you for any help

Answer 1

You could just store the link to which it needs to be redirected in a new column CATEGORY_URL along with the CATEGORY_NAME and then print it out like so:
$query = "SELECT CATEGORY_NAME, CATEGORY_URL FROM CATEGORIES ORDER BY CATEGORY_ID ASC";
$results = mysqli_query($conn, $query);
$numrows = mysqli_num_rows($results);
if ($numrows > 0) {
echo '
<table>
<tr>
<td><strong>Categories</stong></td>
</tr>';
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)) {
echo '
<tr>
<td>
'.$row['CATEGORY_NAME'].'
</td>
</tr>';
}
mysqli_free_result ($results);
} else {
// no results found
}
OR if you just want to pass it as a url parameter, you just need to modify if like so:
'.$row['CATEGORY_NAME'].'
OR
'.$row['CATEGORY_NAME'].'

Answer 2

Something like? (I'm not 100% sure if I understand your question)
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)) {
echo '<tr>
<td><a href="somelink.php?cat=' . $row['CATEGORY_NAME'] . '">' .
$row['CATEGORY_NAME'] . '</a></td>
</tr> ';
}
UPDATE
If a category is named playstation, playstation.php would be linked to...
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)) {
echo '<tr>
<td><a href="' . $row['CATEGORY_NAME'] . '.php">' .
$row['CATEGORY_NAME'] . '</a></td>
</tr> ';
}
Though above would work a wild guess is that you're looking for something completely different. The thing you are looking for is essentially a way to present information for playstation, a way to present information about PS4 etc depending on what user clicks on!? In that case you should do something like this instead:
//Include ID of category in your sql-statement
$query = "SELECT ID, CATEGORY_NAME
FROM CATEGORIES ORDER BY CATEGORY_ID ASC";
....
....
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)) {
echo '<tr>
<td><a href="presentinfo.php?id=' . $row['ID'] . '">' .
$row['CATEGORY_NAME'] . '</a></td>
</tr> ';
}
and create presentinfo.php file where you fetch information about the category, based on the id given in the url. (e.g.select from categories id={id given in url})