Lets say I have this string:
CNVFJD-0905-05-BX
CNV will always be there , same with the first '-'.
What I need is to 'extract' whats between CNV and the first line(in this example I would need 'FJD'.
I don't really know how to approach this.
Thank you.
You can use substr, try this
substr($sring, 3, strpos($string, '-'));
With sscanf:
$str = "CNVFJD-0905-05-BX";
sscanf($str, "CNV%[A-Z]-", $result);
echo $result;
$parts = explode("-", $string);
$result = substr($parts[0], 3);
See here for working example https://3v4l.org/pRJ3e
Related
I have this string:
"application/controllers/backend"
I want get:
backend
of course the backend it's dynamic, so could be change, so I'm looking for a solution that allow me to get only the last part of the string. How I can do that?
You can take the advantage of basename() to get the last part
in your case, it will be
basename("application/controllers/backend");
Output:
backend
Some thing like this :
echo end(explode("/", $url));
If this thorws error then do :
$parts = explode("/", $url);
echo end($parts);
$arr = explode ("/", $string);
//$arr[2] is your third element in the string
http://php.net/manual/en/function.explode.php
Just use
basename("application/controllers/backend");
http://php.net/manual/en/function.basename.php
And, if you want to do it with a regex:
$result = (preg_match('%.*[/\\\\](.*?)$%', $url, $regs)) ? $regs[1] : '';
You did ask initially for a solution with regex, so, although the other answers haven't involved regex, here is one approach which does.
You can use preg_match and str_replace for this:
$string = '"application/controllers/backend"';
preg_match('/[^\/]+"/', $string, $matches);
$last_item = str_replace('"','',$matches[0]);
$last_item is now a string containing the word backend.
I'm new to PHP and I have a problem.
I need delete all chars since a symbol (Sorry for my bad english , i'm from argentina)
I have this text :
3,94€
And I need the text is as follows:
3,94
I tried this by multiple ways but it didn't work.
There are a few ways you can do this:
Using strpos:
$string = '3,94€';
echo substr($string, 0, strpos($string, '&'));
or using strstr:
// Requires PHP 5.3+ due to the true (before_needle) parameter
$string = '3,94€';
echo strstr($string, '&', true);
or using explode:
// Useful if you need to keep the € part for later
$string = '3,94€';
list($part_a, $part_b) = explode('&', $string);
echo $part_a;
or using reset:
$string = '3,94€';
echo reset(explode('&', $string));
The best suited in your case would be to use strpos to find the first occurrence of & in the string, and then use substr to return the string from the begining until the value returned by strpos.
Another posibility is clean the number and then round it:
<?php
//Option 1: with regular expresions:
$val = '3,94€';
$res = preg_replace('/[^0-9.,]/','',$val);
var_dump($res);
//Option 2: with filter functions:
$res2 = filter_var($val, FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION | FILTER_FLAG_ALLOW_THOUSAND);
var_dump($res2);
//Output: 3,948364
//If you want to round it:
$res = substr($res, 0, 4);
var_dump($res);
?>
You can use regex: https://regex101.com/r/uY0kH3/1
It will work in preg_match() function.
You could use str_replace.
<?php
$string = 3,94€
$final = str_replace('€' ,'', $string);
echo $final;
I need to split number with length 5 (example "11111") into two parts with space like "111 11".
What am I missing in my code?
$zip = "11111";
$res = preg_replace('/^\d{3}[ ]?\d{2}/', '$0 $2', $zip);
echo $zip; // returns 11111
echo $res; // returns 11111
Thank you very much
Thanks to all, I missed simple brackets ()
I need to use this to little bit difficult methods :)
Do you really need a regex for this? If it is always a five digit number it's easy to break it apart and reconstruct it as necessary..
echo sprintf("%s %s", substr($zip, 0, 3), substr($zip, -2));
See it in action
John Conde’s answer is great, but since your question is:
What am I missing in my code?
my answer is that you have to capture the groups with parentheses:
$zip = "11111";
$res = preg_replace('/^(\d{3})[ ]?(\d{2})/', '$1 $2', $zip);
echo $zip;
echo PHP_EOL;
echo $res;
Why use a regex for something so simple?
$zip = '11111';
$first_part = substr($zip, 0, 3);
$last_part = substr($zip, 3);
As for your regex, you're not using capture groups ((...)), so $0/$2 will never get defined.
I have string that will look like this:
$string = "hello, my, name, is, az";
Now I just wanna echo whatever is there before first comma. I have been using following:
echo strstr($this->tags, ',', true);
and It has been working great, but the problem it only works php 5.3.0 and above. I am currently on PHP 5.2.
I know this could be achieve through regular express by pregmatch but I suck at RE.
Can someone help me with this.
Regards,
<?php
$string = "hello, my, name, is, az";
echo substr($string, 0, strpos($string, ','));
You can (and should) add further checks to avoid substr if there's no , in the string.
Use explode than,
$arr = explode(',', $string,2);
echo $arr[0];
You can explode this string using comma and read first argument of array like this
$string = "hello, my, name, is, az";
$str = explode(",", $string, 2);
echo $str[0];
$parts = explode(',',$string);
echo $parts[0];
You can simple use the explode function:
$string = "hello, my, name, is, az";
$output = explode(",", $string);
echo $output[0];
Too much explosives for a small work.
$str = current(explode(',', $string));
How can I use str_replace method for replacing a specified portion(between two substrings).
For example,
string1="www.example.com?test=abc&var=55";
string2="www.example.com?test=xyz&var=55";
I want to replace the string between '?------&' in the url with ?res=pqrs&. Are there any other methods available?
You could use preg_replace to do that, but is that really what you are trying to do here?
$str = preg_replace('/\?.*?&/', '?', $input);
If the question is really "I want to remove the test parameter from the query string" then a more robust alternative would be to use some string manipulation, parse_url or parse_str and http_build_query instead:
list($path, $query) = explode('?', $input, 2);
parse_str($query, $parameters);
unset($parameters['test']);
$str = $path.'?'.http_build_query($parameters);
Since you're working with URL's, you can decompose the URL first, remove what you need and put it back together like so:
$string1="www.example.com?test=abc&var=55";
// fetch the part after ?
$qs = parse_url($string1, PHP_URL_QUERY);
// turn it into an associative array
parse_str($qs, $a);
unset($a['test']); // remove test=abc
$a['res'] = 'pqrs'; // add res=pqrs
// put it back together
echo substr($string1, 0, -strlen($qs)) . http_build_query($a);
There's probably a few gotchas here and there; you may want to cater for edge cases, etc. but this works on the given inputs.
Dirty version:
$start = strpos($string1, '?');
$end = strpos($string1, '&');
echo substr($string1, 0, $start+1) . '--replace--' . substr($string1, $end);
Better:
preg_replace('/\?[^&]+&/', '?--replace--&', $string1);
Depending on whether you want to keep the ? and &, the regex can be mofidied, but it would be quicker to repeat them in the replaced string.
Think of regex
<?php
$string = 'www.example.com?test=abc&var=55';
$pattern = '/(.*)\?.*&(.*)/i';
$replacement = '$1$2';
$replaced = preg_replace($pattern, $replacement, $string);
?>