I want to print PHP query with parameters - php

Question

I have the following code
$name = 'myname';
$mail = 'my#mail.it';
$qwt = "INSERT INTO `agenz` (`name`, `email`) VALUES (?,?)";
$result = $connessione->prepare($qwt);
$result->bind_param('ss', $name, $mail);
$result->execute();
I want print the query
"INSERT INTO `agenz` (`name`, `email`) VALUES ('myname','my#mail.it')"
for creating a log.So how to do that?
thanx.

Answer 1

Try fullQuery like below:
$name = 'myname';
$mail = 'my#mail.it';
$qwt = "INSERT INTO `agenz` (`name`, `email`) VALUES (?,?)";
$result = $connessione->prepare($qwt);
$result->bind_param('ss', $name, $mail);
$result->execute();
echo $result->fullQuery;
or
$result->debugQuery();
var_dump($result->debugBindedVariables());
if you want to get the error
var_dump($result->errno);

Answer 2

I have solved!
$qwt = "INSERT INTO `age` (`name`,`email`) VALUES (?,?)";
$par = array($name, $mail);
$result = $connessione->prepare($qwt);
$result->bind_param('ss', $par[0], $par[1]);
$result->execute();
echo "contenuto: " .SqlDebug($qwt, $par);
function SqlDebug($raw_sql, $params=array())
{
$keys = array();
$values = $params;
foreach ($params as $key => $value)
{
// check if named parameters (':param') or anonymous parameters ('?') are used
if (is_string($key)) { $keys[] = '/:'.$key.'/'; }
else { $keys[] = '/[?]/'; }
// bring parameter into human-readable format
if (is_string($value)) { $values[$key] = "'" . $value . "'"; }
elseif (is_array($value)) { $values[$key] = implode(',', $value); }
elseif (is_null($value)) { $values[$key] = 'NULL'; }
}
$raw_sql = preg_replace($keys, $values, $raw_sql, 1, $count);
return $raw_sql;
}

Answer 3

You can use variable directly in the statement like following
$name="ABC";
$mail="me#someone.com";
$value= "I am $name mail id $mail";