I'm trying to see whether or not 2 strings match.
example: 1234.5678.9012.3456 => 5678.1234.3456 = match
This matches because the second string of number are also in the first one. I did this with the following code:
<?php
$haystack = '1234.5678.9012.3456';
$needle = '5678.1234.3456';
$regex = '/(?=.*'. str_replace(".",")(?=.*",$needle) .').*$/';
// regex looks like this /(?=.*5678)(?=.*1234)(?=.*3456).*$/
if(preg_match($regex, $haystack)){
echo "A match was found.";
} else {
echo "A match was not found.";
}
?>
Here is my problem, when there are duplicate numbers.
example: 1234.5678.9012.3456 => 5678.5678.3456 = dont match
1234.5678.5678.3456 => 5678.5678.3456 = match
The first example doesnt match because 5678 occurs twice but the first string only has 5678 once. In the second example 5678 occurs twice as well and therefor matches the second string.
My question: How could I change my regex,
You choose a very complicated way to do that. You can check what you want in a more simple way using array_diff:
var_dump(array_diff(explode('.', $needle), explode('.', $haystack)));
when the resulting array is empty the condition is true.
Try this:
<?php
$haystack = '1234.5678.9012.3456';
$needle = '5678.5678.3456';
$needle_array = explode(".", $needle);
//print_r($needle_array);
$haystack_array = explode(".", $haystack);
//print_r($haystack_array);
$intersect = array_intersect($needle_array, $haystack_array);
//print_r($intersect);
if(count($intersect) > 0){
echo "Match";
} else {
echo "Doesn't match";
}
?>
Related
Sorry, a bit new to php. Have tried all I know, but failed and seeking expert help.
I have a string similar to this..
/%mydocs%/%myfolder%/%date%/%filename%.html
Basically the %vars% represents different strings and seperated by /, like a URL.
I need to find %date% (or any given variable) if it's present and it's position in the string, like it's at position 3 in the example above.
I tried this,
$date = preg_match( '%date%', '/%mydocs%/%myfolder%/%date%/%filename%.html');
But it's neither returning anything nor the position.
Any help, even some heads up to play with, will be appriciated.
strpos
<?php
$mystring = '/%mydocs%/%myfolder%/%date%/%filename%.html';
$findme = '%date%';
$pos = strpos($mystring, $findme);
if ($pos === false) {
echo "The string '$findme' was not found in the string '$mystring'";
} else {
echo "The string '$findme' was found in the string '$mystring'";
echo " and exists at position $pos";
}
?>
Result:
The string '%date%' was found in the string '/%mydocs%/%myfolder%/%date%/%filename%.html' and exists at position 21
How about using preg_split:
$var = '%date%';
$str = '/%mydocs%/%myfolder%/%date%/%filename%.html';
$list = preg_split('#/#', $str, -1, PREG_SPLIT_NO_EMPTY);
for($i=0; $i<count($list); $i++) {
if ($list[$i] == $var) {
echo "Found $var at position ",$i+1,"\n";
}
}
output:
Found %date% at position 3
preg_match returns a boolean for whether there was a match or not, but you can pass a third parameter - $matches, which will contain the matches according to the regular expression provided.
You don't look to be using a regular expressions - for what you are doing you probably want to look at strpos instead. http://uk3.php.net/strpos
Currently I have this code:
<?php
if (isset($_GET['id'])) {
$itemid = $_GET['id'];
$search = "$itemid";
$query = ucwords($search);
$string = file_get_contents('http://clubpenguincheatsnow.com/tools/newitemdatabase/items.php');
if($itemid=="")
{
echo "Please fill out the form.";
}
else
{
$string = explode('<br>',$string);
foreach($string as $row)
{
preg_match('/^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/', trim($row), $matches);
if(strstr($matches[1], $query))
{
echo "<a href='http://clubpenguincheatsnow.com/tools/newitemdatabase/info.php?id=$matches[2]'>";
echo $matches[1];
echo "</a><br>";
}
}
if($matches[1]=="")
{
echo "Item does not exist!";
}
}
}
else {
echo "Item does not exist!";
}
?>
What I want to know is what does this section mean? preg_match('/^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/', trim($row), $matches); mainly the /^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/ part is what I am wondering about.
Also, an issue that I have been having is how can I allow it to use numbers too? Because I have another file that has the data (http://clubpenguincheatsnow.com/tools/newitemdatabase/items.php) and it want it to grab everything, even the names with the numbers.
How do I do this though? Please help me! Any help would be VERY HIGHLY appreciated!
That is a regular expression.
The '^' matches the beginning of a string.
The '\D' matches any character that is not a digit.
The '\d' matches any digit.
The '\s' matches any whitespace.
The plus sign means that the previous character can occur multiple times.
So basically it would match all those lines in your file, except that last comma.
Blue = 1 = No = 20
That line would match the regex.
About your last question to allow numbers too, use this:
/^(.+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/
the code is a regular expression:
/^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/
the code will use the regular expression to cut the string um pieces and put in an array ($matches)
preg_match('/^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/', trim($row), $matches);
You shall use the code to see better
print_r($matches)
To find by name or by item number change the code
if(strstr($matches[1], $query))
to
if(isset($matches[1]) && (strstr($matches[1], $query) || $matches[2] == $query) )
Your code shall look like this...
if (isset($_GET['id'])) {
$itemid = $_GET['id'];
$search = "$itemid";
$query = ucwords($search);
$string = file_get_contents('http://clubpenguincheatsnow.com/tools/newitemdatabase/items.php');
if($itemid=="")
{
echo "Please fill out the form.";
}
else
{
$string = explode('<br>',$string);
foreach($string as $row)
{
preg_match('/^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/', trim($row), $matches);
if(isset($matches[1]) && (strstr($matches[1], $query) || $matches[2] == $query) )
{
echo "<a href='http://clubpenguincheatsnow.com/tools/newitemdatabase/info.php?id=$matches[2]'>";
echo $matches[1];
echo "</a><br>";
}
}
}
}
else {
echo "Item does not exist!";
}
/^(\D+)\s=\s(\d+)\s=\s(\D+)\s=\s(\d+)/
This regular expression will match any number of non-numeric character, followed by a whitespace character, followed by equals, and so on. For example, this
asd = 1 = yh = 23
To allow numbers in the names:
/^(\w+)\s=\s(\d+)\s=\s(\w+)\s=\s(\d+)/
To allow numbers and alpha-numeric chars in everything:
/^(\w+)\s=\s(\w+)\s=\s(\w+)\s=\s(\w+)/
To include spaces and ' too:
/^([\w\s']+)\s=\s([\w\s']+)\s=\s([\w\s']+)\s=\s([\w\s']+)/
The code, as said by Sena, is a regular expression. It is capturing four groups with "=" in between them.
group 1: (\D+) : any character that is not a digit one or more times
group 2: (\d+) : any character that is a digit one or more times
group 3: (\D+) : same as one
group 4: (\d+) : same as two.
So, it will match something like this: a = 1 = bc = 2
So, it is matching numbers, what do you want it to do? try print_r($matches) as suggested above.
How do I find exact 2, in a string using strpos? Is it possible using strpos? The example below returns "Found" even though the match is NOT exact to what I need. I understand 2, is matching with 22,. It should return "Not Found". I am matching ID's in this example.
$string = "21,22,23,26,";
$find = "2,";
$pos = strpos($string, $find);
if ($pos !== false) {
echo "Found";
} else {
echo "Not Found";
}
Unless the string is enormous, make an array and search it:
$string = "21,22,23,26,";
$arr = explode(",", $string);
// array_search() returns its position in the array
echo array_search("2", $arr);
// null output, 2 wasn't found
Actually, in_array() is probably faster:
// in_array() returns a boolean indicating whether it is found or not
var_dump(in_array("2", $arr));
// bool(false), 2 wasn't found
var_dump(in_array("22", $arr));
// bool(true), 22 was found
This will work as long as your string is a comma-delimited list of values. If the string is really long, making an array may be wasteful of memory. Use a string manipulation solution instead.
Addendum
You didn't specify, but if by some chance these strings came from a database table, I would just add that the appropriate course of action would be to properly normalize it into another table with one row per id rather than store them as a delimited string.
Try with explode and in_array
Example:
$string = "21,22,23,26,";
$string_numbers = explode(",", $string);
$find = 2;
if (in_array($find, $string_numbers)) {
echo "Found";
} else {
echo "Not Found";
}
You can use preg_match if you want to avoid arrays.
$string = "21,22,23,26,";
$find = '2';
$pattern = "/(^$find,|,$find,|,$find$)/";
if (0 === preg_match($pattern, $string)) {
echo "Not Found";
} else {
echo "Found";
}
This will find your id at beginning, middle or at the end of the string. Of course, I am assuming $string does not contain characters other than numbers and commas (like spaces).
I have a string
8,7,13,14,16
Whats the easiest way to determine if a given number is present in that string?
$numberA = "13";
$string = "8,7,13,14,16";
if($string magic $numberA){
$result = "Yeah, that number is in there";
} else {
$result = "Sorry.";
}
Looking for magic.
<?php
in_array('13', explode(',', '8,7,13,14,16'));
?>
…will return whether '13' is in the string.
Just to elaborate: explode turns the string into an array, splitting it at each ',' in this case. Then, in_array checks if the string '13' is in the resulting array somewhere.
Another way, that might be more efficient for laaaaaaaarge strings, is using a regexp:
$numberA = "13";
$string = "8,7,13,14,16";
if(preg_match('/(^|,)'.$numberA.'($|,)/', $string)){
$result = "Yeah, that number is in there";
} else {
$result = "Sorry.";
}
if (strpos(','.$string.',' , ','.$numberA.',') !== FALSE) {
//found
}
Notice guard ',' chars, they will help to deal with '13' magic '1, 2, 133' case.
Make sure you match the full number in the string, not just part of it.
function numberInList($num, $list) {
return preg_match("/\b$num\b/", $list);
}
$string = "8,7,13,14,16";
numberInList(13, $string); # returns 1
numberInList(8, $string); # returns 1
numberInList(1, $string); # returns 0
numberInList(3, $string); # returns 0
A simple string search should do if you are just checking to find existence of the string. I dont speak php but i think this is how it could be done.
$mystring = '8,7,13,14,16';
$findme = '13';
if (preg_match('/(?>(^|[^0-9])'.$findme.'([^0-9]|$))/', $mystring)) {
$result = "Yeah, that number is in there";
} else {
$result = "Sorry.";
}
I need a simple word filter that will kill a script if it detects a filtered word in a string.
say my words are as below
$showstopper = array(badword1, badword2, badword3, badword4);
$yourmouth = "im gonna badword3 you up";
if(something($yourmouth, $showstopper)){
//stop the show
}
You could implode the array of badwords into a regular expression, and see if it matches against the haystack. Or you could simply cycle through the array, and check each word individually.
From the comments:
$re = "/(" . implode("|", $showstopper) . ")/"; // '/(badword1|badword2)/'
if (preg_match($re, $yourmouth) > 0) { die("foulmouth"); }
in_array() is your friend
$yourmouth_array = explode(' ',$yourmouth);
foreach($yourmouth_array as $key=>$w){
if (in_array($w,$showstopper){
// stop the show, like, replace that element with '***'
$yourmouth_array[$key]= '***';
}
}
$yourmouth = implode(' ',$yourmouth_array);
You might want to benchmark this vs the foreach and preg_match approaches.
$showstopper = array('badword1', 'badword2', 'badword3', 'badword4');
$yourmouth = "im gonna badword3 you up";
$check = str_replace($showstopper, '****', $yourmouth, $count);
if($count > 0) {
//stop the show
}
A fast solution involves checking the key as this does not need to iterate over the array. It would require a modification of your bad words list, however.
$showstopper = array('badword1' => 1, 'badword2' => 1, 'badword3' => 1, 'badword4' => 1);
$yourmouth = "im gonna badword3 you up";
// split words on space
$words = explode(' ', $yourmouth);
foreach($words as $word) {
// filter extraneous characters out of the word
$word = preg_replace('/[^A-Za-z0-9]*/', '', $word);
// check for bad word match
if (isset($showstopper[$word])) {
die('game over');
}
}
The preg_replace ensures users don't abuse your filter by typing something like bad_word3. It also ensures the array key check doesn't bomb.
not sure why you would need to do this but heres a way to check and get the bad words that were used
$showstopper = array(badword1, badword2, badword3, badword4);
$yourmouth = "im gonna badword3 you up badword1";
function badWordCheck( $var ) {
global $yourmouth;
if (strpos($yourmouth, $var)) {
return true;
}
}
print_r(array_filter($showstopper, 'badWordCheck'));
array_filter() returns an array of bad words, so if the count() of it is 0 nothign bad was said