i have SQL query :
SELECT countryCode FROM itins_countries WHERE (itinID = 5);
$countriesIndex = mysql_fetch_array($countriesQuery);
now, in another art of my code I would like to run on the "$countriesIndex" and print all the values it contain ("countryCode");
how can i do that?
while($row = mysql_fetch_array($countriesQuery)){
echo $row['column_name'];
///same for other columns
}
you can use the while loop to loop until all the array element has been printed
try this....
echo "<pre>";print_r($countriesIndex);
mysql_connect is deprecated...you can use mysqli_connect.
$mysqli = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME);
if (mysqli_connect_errno($mysqli)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
mysqli_set_charset($mysqli, "utf8");
$sql = "SELECT countryCode FROM itins_countries WHERE (itinID = 5)";
$result = mysqli_query($mysqli, $sql);
$countries = [];
while($row = $result->fetch_assoc())
{
$users_arr[] = $row;
}
$result->close();
print_r($users_arr);
Related
Adapting an answer from here to try and pass an array as the parameter for a WHERE clause in MySQL. Syntax seems okay but I'm just getting null back form the corresponding JSON. I think understand what it is supposed to do, but not enough that I can work out where it could be going wrong. The code for the function is;
public function getTheseModulesById($moduleids) {
require_once 'include/Config.php';
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD);
// Check connection
if (!$con)
{
die("Connection error: " . mysqli_connect_error());
}
// selecting database
mysqli_select_db($con, DB_DATABASE) or die(mysqli_connect_error());
$in = join(',', array_fill(0, count($moduleids), '?'));
$select = "SELECT * FROM modules WHERE id IN ($in)";
$statement = $con->prepare($select);
$statement->bind_param(str_repeat('i', count($moduleids)), ...$moduleids);
$statement->execute();
$result = $statement->get_result();
$arr = array();
while($row = mysqli_fetch_assoc($result)) {
$arr[] = $row;
}
mysqli_close($con);
return $arr;
}
And the code outwith the function calling it looks like;
$id = $_POST['id'];
$player = $db->getPlayerDetails($id);
if ($player != false) {
$pid = $player["id"];
$moduleids = $db->getModulesByPlayerId($pid); //this one is okay
$modules = $db->getTheseModulesById($moduleids); //problem here
$response["player"]["id"] = $pid;
$response["player"]["fname"] = $player["fname"];
$response["player"]["sname"] = $player["sname"];
$response["modules"] = $modules;
echo json_encode($response);
[EDIT]
I should say, the moduleids are strings.
I have a SQL table (modules) with two columns (id, name). Now I can retrieve the rows from this through a PHP script but what I want is to use the value of id as the key, and the value of name as the value, in a multidimensional array. Then I want to be able to encode those into a JSON, retaining the relationship between key/value. I've muddled something together but it returns null.
the relevant code from index.php
$mod1 = $core["module1"];
$mod2 = $core["module2"];
$modules = $db->getModulesById($mod1, $mod2); //module names & ids
$response["module"]["mod1"] = $modules[$mod1];
$response["module"]["mod2"] = $modules[$mod2];
$response["module"]["mod1name"] = $modules[$mod1]["name"];
$response["module"]["mod2name"] = $modules[$mod2]["name"];
echo json_encode($response);
The function from DB_Functions.php
public function getModulesById($mod1, $mod2) {
require_once 'include/Config.php';
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD);
// Check connection
if (!$con)
{
die("Connection error: " . mysqli_connect_error());
}
// selecting database
mysqli_select_db($con, DB_DATABASE) or die(mysqli_connect_error());
$query = "SELECT * FROM modules WHERE id= '$mod1' OR id='$mod2'";
$result = mysqli_query($con, $query);
$arr = array();
while($row = mysqli_fetch_assoc($result)) {
// process each row
//each element of $arr now holds an id and name
$arr[] = $row;
}
// return user details
return mysqli_fetch_array($arr);
close();
}
I've looked around but I'm just not 'getting' how the query return is then broken down into key/value for a new array. If someone could ELI5 I'd appreciate it. I'm just concerned with this aspect, it's a personal project so I'm not focusing on security issues as yet, thanks.
You are pretty well there
public function getModulesById($mod1, $mod2) {
require_once 'include/Config.php';
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
// Check connection
if (!$con) {
die("Connection error: " . mysqli_connect_error());
}
$query = "SELECT * FROM modules WHERE id= '$mod1' OR id='$mod2'";
$result = mysqli_query($con, $query);
$arr = array();
while($row = mysqli_fetch_assoc($result)) {
$arr[] = $row;
}
// here is wrong
//return mysqli_fetch_array($arr);
// instead return the array youy created
return $arr;
}
And call it and then just json_encode the returned array
$mod1 = $core["module1"];
$mod2 = $core["module2"];
$modules = $db->getModulesById($mod1, $mod2); //module names & ids
$response['modules'] = $modules;
echo json_encode($response);
You should really be using prepared and paramterised queries to avoid SQL Injection like this
public function getModulesById($mod1, $mod2) {
require_once 'include/Config.php';
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
// Check connection
if (!$con) {
die("Connection error: " . mysqli_connect_error());
}
$sql = "SELECT * FROM modules WHERE id= ? OR id=?";
$stmt = $con->prepare($sql);
$stmt->bind_param('ii', $mod1, $mod2);
$stmt->execute();
$result = $stmt->get_result();
$arr = array();
while($row = mysqli_fetch_assoc($result)) {
$arr[] = $row;
}
// here is wrong
//return mysqli_fetch_array($arr);
// instead return the array youy created
return $arr;
}
mysqli_fetch_array requires the result of a mysqli_query result. Passing the constructed array to mysqli_fetch_array() is not going to work.
If you want to have a specific value from a row to use as its key, you can't resolve this with any mysqli_* function. You could however construct it yourself:
while($row = mysqli_fetch_assoc($result)) {
// process each row
//each element of $arr now holds an id and name
$arr[$row['id']] = $row;
}
mysqli_close($con);
return $arr;
You should close the connection before returning the result, code positioned after a return will not be executed.
I want to print result of a Mysqli query, But when I try to do as following way, It does not return any values or error. The code does not go through the while loop. What would be the wrong with my code, Please help me!
<?php
$mysqli = new mysqli("localhost", "root", "", "domains");
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$part = explode(".", $str);
$part1 = $part[0];
$part2 = $part[1];
$sql = "SELECT
DomainCategory.Name
FROM
DomainName_Client,
DomainNameType,
DomainCategory,
OrderDomain_Client
WHERE
DomainName_Client.Name = '$part1'
AND DomainNameType.Name = '$part2'
AND DomainName_Client.TypeID = DomainNameType.ID
AND DomainCategory.ID = DomainName_Client.DomainCategoryID
AND OrderDomain_Client.DomainNameID = DomainName_Client.ID";
$result = $mysqli->query($sql);
if (!$result = $mysqli->query($sql)) {
die('There was an error running the query ' . $mysqli->error . ']');
}
while ($row = $result->fetch_assoc()) {
echo 'Total results: ' . $result->num_rows;
}
?>
First you check the number of results returning in the sql query using the following code and after that you print it using while or for loop.
echo $result->num_rows;
I have a working SQL query that I'm trying to use in a small PHP script but getting Parse error, tried many variations. Hope you can help. End result would be to have a two field form with 'Date' and 'Channel No' then giving result count of number of 'channel' rows for a given date. Sorry fairly new PHP/SQL, thanks.
<?php
// Connect to MSSQL and select the database
$link = mssql_connect('localhost', 'root', '', 'jm_db');
mssql_select_db('jm_db');
// Select all our records from a table
$mysql_query = mssql_query ('SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%');
echo $sql;
?>
I have re-done the code but getting 'Warning: mysql_fetch_array() expects parameter 1 to be resource' and undefined variable.
<?php
// Create connection
$mysqli = new mysqli($localhost, $root, $jm_db);
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$sql = ("SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%'");
$results= array();
while ($result = mysql_fetch_array($sql)) {
$results[]= $result;
}
foreach($results as $result){
echo $result['calldate'] . " " . $result['channel'];
}
?>
You're missing a quote (Stack's syntax highlighting shows you), yet it should be replaced with an opening double quote and ending with the same. You can't use all single quotes.
I replaced the opening single quote with a double, along with a matching closing double quote.
$mysql_query = mssql_query ("SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%'");
As a sidenote, you're echoing the wrong variable.
However, that is not how you would echo out results, but with a loop.
Something like, and replacing Fieldname with the one you want to use:
while ($row = mssql_fetch_assoc($mysql_query)) {
print $row['Fieldname'] . "\n";
}
or use mssql_fetch_array()
You can also use:
$results= array();
while ($result = mssql_fetch_array($mysql_query)) {
$results[]= $result;
}
foreach($results as $result){
echo $result['calldate'] . " " . $result['channel'];
}
For more information on Microsoft SQL Server's function, consult:
http://php.net/manual/en/book.mssql.php
$mysql_query = mssql_query ('SELECT COUNT(*) FROM asterisk_cdr
WHERE calldate LIKE '%2014-10-11%'
AND channel LIKE '%SIP/4546975289%');
while($row=mssql_fetch_array($mysql_query))
{
echo $row[0];
}
$mysqli = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($mysqli->connect_error) {
die("Connection failed: " . $mysqli->connect_error);
}
$mysql_query = mysqli ("SELECT COUNT(*) FROM asterisk_cdr WHERE calldate LIKE '%2014-10-11%' AND channel LIKE '%SIP/4546975289%'");
while ($row = mysql_fetch_array($mysql_query, MYSQL_ASSOC)) {
echo ($row["channel"]);
}
this is a simple example with PDO
<?php
try {
$dns = 'mysql:host=localhost;dbname=jm_db';
$user = 'root';
$pass = '';
$options = array(
PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8",
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
);
$cnx = new PDO( $dns, $user, $pass, $options );
$select = $cnx->query("SELECT COUNT(*) as count FROM asterisk_cdr WHERE calldate LIKE '%2014-10-11%' AND channel LIKE '%SIP/4546975289%'");
$select->setFetchMode(PDO::FETCH_OBJ);
while( $row = $select->fetch() )
{
echo '<h1>', $row->count , '</h1>';
}
} catch ( Exception $e ) {
echo "Connect failed : ", $e->getMessage();
die();
}
I have a simple script that I am trying to understand why it will not work, and how to get exactly what I want.
What I want to get is an array, call it $results and have the data stored as follows
$results ->
$row1 ->
$field1
$field2
$field3
$field4
$field5
$row2 ->
$field1
$field2
$field3
$field4
$field5
etc...
but I cant even get the mysqli to loop out the results at all, here is my code...
require_once ('lib/constants.php');
$mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME) or die('Error connecting to Database.');
$query = "SELECT * FROM employees LIMIT 0, 20";
if($stmt = $mysqli->prepare($query)) {
$stmt->execute();
$row = array();
stmt_bind_assoc($stmt, $row);
while($stmt->fetch()) {
var_dump($row);
}
}
Please check mysqli_result::fetch_assoc method on PHP.net for better understanding.
Below is a quick example
require_once ('lib/constants.php');
$mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME) or die('Error connecting to Database.');
$query = "SELECT * FROM employees LIMIT 0, 20";
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
echo $row['myfield'];
}
/* free result set */
$result->free();
}
You should check mysqli_result:::fetch_all instead of mysqli_result::fetch_assoc
$query = "SELECT * FROM employees LIMIT 0, 20";
if ($result = $mysqli->query($query)) {
$array_assoc = $result->fetch_all();
/* free result set */
$result->close();
}