Show query result in PHP - php

Question

I have a query:
$string = "SELECT COUNT(id) as sponsered FROM `$database`.`$mem` where parent_id = 2 group by plan";
Which result in:
sponsored plan
2 gold
1 silver
1 mitra
This result is shown when I run this query in MySQL.
Now I want this result in PHP in an array data[] where
data[0] contains 2
data[1] contains 1
data[2] contains 1
I have tried this
$string = "SELECT COUNT(id) as sponsered FROM $database.$mem where parent_id = 2 group by plan";
$res = mysqli_query($con, $string);
while($data = mysqli_fetch_assoc($res)) {
echo $data['sponsered'];
}
But it results in data['sponsered'] containing 211
It would be better if this can be done without using any loop.

Answer 1

Inside the while loop assign the values to array.
$string = "SELECT COUNT(id) as sponsered FROM $database.$mem where parent_id = 2 group by plan";
$res = mysqli_query($con, $string);
$data = array();
while($result = mysqli_fetch_assoc($res)) {
$data[] = $result['sponsered'];
}
print_r($data);
Output:
data[0] contains 2
data[1] contains 1
data[2] contains 1

Answer 2

Your display is correct you just need a separator so the data isn't all clumped. In a browser:
echo $data['sponsered'] . "<br>";
in your loop should do it, or command line,
echo $data['sponsered'] . PHP_EOL;
should do it.
As is it throws 2, then 1, then 1 which views as 211.

Answer 3

Try this:
Please refrain from passing data directly into query in a prepare statement, use ? or : as deemed necessary.
Below is a sample code:
<?php
$table_name = $table; //not recommended to pass table_name as variable, unless necessary.
$parent_id = 2;
$p = $plan;
$string = "SELECT COUNT(id) as sponsered FROM $table_name where parent_id = ? group by ?";
if ($stmt = $db->prepare($string))
{
$stmt->bind_param('is', $parent_id, $p);
$stmt->execute();
$stmt->bind_result($sponsored, $plan);
$stnt->store_result();
$html ='';
while ($stmt->fetch() !== FALSE)
{
// Do what you like with the variables here, i.e. $sponsored, $plan
$html .= "<table>
<th> Sponsored </th>
<th> Plan</th>
<tr>
<td>$sponsored</td>
<td>$plan</td>
</tr>
</table>";
}
else {
die("Query failed");
}
var_dump($html);
}
?>
NOTE: If your result from your question is just an HTML (table/column), you don't need to do bind, you can just output the HTML formatted.

Answer 4

Use mysqli_fetch_array($result, MYSQLI_NUM) to retreive the data as numeric array