How to get next ID on next page PHP - php

I want to read the different ID on different page, by using the prev/next button.
If I click next button, I want to get the next ID, if I click previous button, it will back to the previous ID. Following is what I want.
Example:
testnext_pre1.php?id=1&page=1
testnext_pre1.php?id=2&page=2
testnext_pre1.php?id=5&page=3
Here is my problem. As you can see, I get the same ID on every page because of my code. How to get the correct ID for the page?
Please take note: the IDs are not increase by sequence, as some contents might be deleted. So I don't want the answer something like "+1".
$rowsPerPage = 1;
if(isset($_GET['page']))
{
$pageNum= $_GET['page'];
}
else
{
$pageNum = 1;
}
// preceding rows
$previousRows =($pageNum - 1) * $rowsPerPage;
$query = "SELECT * FROM news LIMIT $previousRows, $rowsPerPage";
$result = mysql_query($query) or die('Error couldn\'t get the data').mysql_error();
echo "<table border=1>\n";
echo "<tr><th>ID</th><th>Name</th><th>Password</th><th>Perm</th><th>Email</th>
<th>Date</th></tr>";
// print the results
while(list($id,$name,$pass,$perm,$email,$date) = mysql_fetch_array($result))
{
echo "<tr><td>$id</td><td>$name</td><td>$pass</td><td>$perm</td><td>$email</td>
<td>$date</td></tr>";
}
echo '</table>';
$query = "SELECT COUNT(id) AS numrows FROM news";
$result = mysql_query($query) or die('Error, couldn\'t get count title=\"$page\"').mysql_error();
$row = mysql_fetch_assoc($result);
$numrows = $row['numrows'];
$lastPage = ceil($numrows/$rowsPerPage);
$phpself = $_SERVER['PHP_SELF'];
if ($pageNum > 1)
{
$page = $pageNum - 1;
$prev = "<div class=\"paginationbtn floatleft\">previous</div>";
$first = " [First Page] ";
}
else
{
$prev = ' previous ';
$first = ' [First Page] ';
}
if ($pageNum < $lastPage)
{
$page = $pageNum + 1;
$resultid = mysql_query("SELECT id FROM news");
while($loopid=mysql_fetch_array($resultid))
{
$rowid = $loopid['id'];
$next = " <div class=\"paginationbtn floatright\">next</div> ";
}
}
else
{
$next = ' [Next] ';
}
echo $prev . " " . $next;

Just get the previous and next ids from the database
if ($pageNum > 1)
{
//Get previous id using this query
SELECT id FROM news LIMIT $previousRows-1, $rowsPerPage
}
if ($pageNum < $lastPage)
{
//Get next id using this query
SELECT id FROM news LIMIT $previousRows+1, $rowsPerPage
}

Try the following sql query to get the next id,right now you are looping the news table and your next button will always have the same value
if ($pageNum < $lastPage)
{
$page = $pageNum + 1;
$resultid = mysql_query("select id from news where id = (select min(id) from news where id > ".$_GET['id'].")");
while($loopid=mysql_fetch_array($resultid))
{
$rowid = $loopid['id'];
$next = " <div class=\"paginationbtn floatright\">next</div> ";
}
$prevresultid = mysql_query("select id from news where id = (select max(id) from news where id < ".$_GET['id'].")");
while($loopid=mysql_fetch_array($prevresultid))
{
$rowid = $loopid['id'];
$prev= " <div class=\"paginationbtn floatleft\">next</div> ";
}
}
Note: you will need mysqli and prepared statements to secure your code

if you want to set pagination than no need of next id it will mange by query only . and in query we change only offset .
for e.g each page display 3 records so our limit is 3
now if we on first page than our fetch record query is(on first page offset is always 0)
so offset is 0 and limit is 3
SELECT fieldName FROM tableName LIMIT offset,limit
for second page now current offset is 3 so
prev is current_offset minus limit (3-3) so prev offset is 0
next is current_offset plus limit (3+3) so next offset is 6
now in 3rd page current offset is 6
prev is current_offset minus limit (6-3) so prev offset is 3
next is current_offset plus limit (6+3) so next offset is 9

try this one
<?php
$rowsPerPage = 1;
if(isset($_GET['page']))
{
$pageNum= $_GET['page'];
}
else
{
$pageNum = 1;
}
// preceding rows
$previousRows =($pageNum - 1) * $rowsPerPage;
$query = "SELECT * FROM news LIMIT $previousRows, $rowsPerPage";//offset,limit
$result = mysql_query($query) or die('Error couldn\'t get the data').mysql_error();
echo "<table border=1>\n";
echo "<tr><th>ID</th><th>Name</th><th>Password</th><th>Perm</th><th>Email</th>
<th>Date</th></tr>";
// print the results
while(list($id,$name,$pass,$perm,$email,$date) = mysql_fetch_array($result))
{
echo "<tr><td>$id</td><td>$name</td><td>$pass</td><td>$perm</td><td>$email</td>
<td>$date</td></tr>";
}
echo '</table>';
$query = "SELECT COUNT(id) AS numrows FROM news";
$result = mysql_query($query) or die('Error, couldn\'t get count title=\"$page\"').mysql_error();
$row = mysql_fetch_assoc($result);
$numrows = $row['numrows'];
$lastPage = ceil($numrows/$rowsPerPage);
$phpself = $_SERVER['PHP_SELF'];
if ($pageNum > 1)//current page > 1
{
$page = $pageNum - 1;
$prev = "<div class=\"paginationbtn floatleft\">previous</div>";
$first = " [First Page] ";
}
else
{
$prev = ' previous ';
$first = ' [First Page] ';
}
if ($pageNum < $lastPage)
{
$page = $pageNum + 1;
$next_row=$previousRows+1;
$resultid = mysql_query("SELECT id FROM news LIMIT $next_row,1");
while($loopid=mysql_fetch_array($resultid))
{
$rowid = $loopid['id'];
$next = " <div class=\"paginationbtn floatright\">next</div> ";
}
}
else
{
$next = ' [Next] ';
}
echo $prev . " " . $next;

Related

Detect Previous Next ID

I have a little script that have a Previous & Next button.
My problem is I want to detect & place the ID in those buttons
this is the code from the pagination
<body>
<?php include_once 'data.php'; ?>
<center>
<ul class="pagination">
<?php
if($page_counter == 0){
echo "<li><a href=?start='0' class='active'>0</a></li>";
for($j=1; $j < $paginations; $j++) {
echo "";
}
}else{
echo "<a href=?start=$previous><button>Previous</button></a>";
for($j=0; $j < $paginations; $j++) {
if($j == $page_counter) {
echo " ";
}else{
echo " ";
}
}if($j != $page_counter+1)
echo "<a href=?start=$next><button>Next</button></a>";
}
?>
</ul>
</center>
In this part I have the ID but the problem is I can`t get it with this example to place it into the pagination.
<?php
foreach($result as $row) {
echo '
<div class="card"><button1>
'. $row['notice_id'] .'
<div class="time-left">
<div class="dropdown1">
' ;
}
}
else {
echo '';
}
$conn->close();
?>
</div></div>
This is the code from data.php I think I need to place some code into for detection from the ID
<?php
//include configuration file
require 'configuration.php';
$start = 0; $per_page = 1;
$page_counter = 0;
$next = $page_counter + 1;
$previous = $page_counter - 1;
if(isset($_GET['start'])){
$start = $_GET['start'];
$page_counter = $_GET['start'];
$start = $start * $per_page;
$next = $page_counter + 1;
$previous = $page_counter - 1;
}
// query to get messages from messages table
$q = "SELECT * FROM group_notice LIMIT $start, $per_page";
$query = $db->prepare($q);
$query->execute();
if($query->rowCount() > 0){
$result = $query->fetchAll(PDO::FETCH_ASSOC);
}
// count total number of rows in students table
$count_query = "SELECT * FROM group_notice";
$query = $db->prepare($count_query);
$query->execute();
$count = $query->rowCount();
// calculate the pagination number by dividing total number of rows with per page.
$paginations = ceil($count / $per_page);
?>
You can use some formulas for calculate limit and offset of results.
For example you have 100 records, and you want to paginate it into 10 records per page, and the formula is like below.
// Get Page from Query String
$page = 1;
if(!empty($_GET["page"])){
$page = $_GET["page"];
}
// Get record count
$count_query = "SELECT * FROM group_notice";
$query = $db->prepare($count_query);
$query->execute();
$count = $query->rowCount();
$per_page = 10; // records per page
$pages = ceil($count/$per_page); // get total page
$start = $page * $per_page - $per_page; // get offset
// Do something with your records
$query = db->prepare("SELECT * FROM group_notice LIMIT ?, ?");
$query->bind_param("ii", $start, $per_page); // you should use bind param if you use prepared statement
$query->execute();
if($query->rowCount() > 0){
$result = $query->fetchAll(PDO::FETCH_ASSOC);
}
if($page > 1){
echo 'Prev'; // Print Prev Page
}
for($i = 1; $i <= $pages){
echo ''.$i.''; // Print Page Number
}
if($page < $pages){
echo 'Next'; // Print Next Page
}
Hope it helps.

PHP MySQL Paging

I tried so many different solutions. Im new to php since 1 week, used ASP 12 years ago so I hope I can get some help.
Everything down here works fine. But there are around 1000 rows in the db and I need to split them up in pages.
<?php
$con = mysqli_connect("localhost","test","test","test")or die('could not connect to database');
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
echo "<table border='0'>
<tr>
<th>Img:</th>
<th>Text:</th>
</tr>";
$result = mysqli_query($con,"SELECT Jokes.ID, Categories.CategoryName, Jokes.CategoryID, Jokes.JokeText FROM Jokes LEFT JOIN Categories ON Jokes.CategoryID = Categories.ID ORDER BY Jokes.JokeText");
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td align='center'><img src='webimg/" . $row['CategoryName'] . ".png' height='35' width='35'></td>";
echo "<td align='left' width='80%'>" . $row['JokeText'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
Kind Regards.
You can use MySQL LIMIT for that.
I've used to do it like this:
Get the total number of rows you're paging and have a parameter like in the URL, i.e. "/p/5" or ?page=5 (I will use this for reference, easier to write code and for you to understand) for page no. 5, also do a failsafe, like this:
Say you have 10 records per page:
$page = isset($_GET['page']) ? (int) $_GET['page'] : 1;
$records_per_page = 10;
And, in your SQL you will have something like this
$start = ($page-1) * $records_per_page;
$result = mysql_query("select * from table limit {$start}, {$records_per_page}");
Kind of crude, but you should get the point and be on the right path.
For building your pagination links... that's totally up to you. You should get the total amount of rows with a "select count (PRIMARY_KEY) from table" query prior, so you can calculate the max number of pages.
What you're searching for is the LIMIT of mysql.
The usage is very simple.
For example:
"SELECT * FROM tablename LIMIT 3"
This will give you the first three results.
In your case, you need an offset, depends on the current page:
"SELECT * FROM tablename LIMIT offset,results"
The offset can be calculated, depends on how many results you want each page.
"SELECT * FROM tablename LIMIT 20,10"
This will display 10 results, start at result 20. This could be for the 3. site if you want 10 results each site.
<?php
$per_page = 10; //no. of results to display in one page
$pages_query = mysql_query("SELECT COUNT('id') FROM JOKES");//Or whatever field. this is just to check the number of results.
$pages = ceil(mysql_result($pages_query, 0) / $per_page);//to get the total no. of pages that will be there. For example if u have 60 results than no. og pages will be 60/10=6
$page = (isset($_GET['page'])) ? (int)$_GET['page'] : 1;// if the page variable in your url is set that means that u have clicked a page number. So it will be taking that page number and displaying those results
$start = ($page - 1) * $per_page;//to get the starting result of that page. If you are in say 6th page, then the starting element would be 6-1*10=50. This makes sure that the results in the previous pages are not displayed
$query = mysql_query("SELECT * FROM JOKES LIMIT $start, $per_page");//set the limit of results that page
while($query_row = mysql_fetch_assoc($query)){
echo " ur table names ";
}
$prev = $page - 1;//to set the prev page variable
$next = $page + 1;//to set the next page variable
if(!($page<=1)){
echo "<a href='Yourpagename.php?page=$prev'>Prev</a> ";
}//does not displays the prev variable if you are already one first page
if($pages>=1 && $page<=$pages){
for($x=1;$x<=$pages;$x++){
echo ($x == $page) ? '<strong>'.$x.'</strong> ' : ''.$x.' ';
}//display all the pages. Display the current page as bold
}
if(!($page>=$pages)){
echo "<a href='Your page name.php?page=$next'>Next</a>";
}//do not display next vvariable if your are in the last page
?>
Thx for all the answers. I came over this tutorial and it worked: http://www.developphp.com/view.php?tid=1349
<?php
include_once("mysqli_connection.php");
$sql = "SELECT COUNT(id) FROM testimonials WHERE approved='1'";
$query = mysqli_query($db_conx, $sql);
$row = mysqli_fetch_row($query);
$rows = $row[0];
$page_rows = 10;
$last = ceil($rows/$page_rows);
if($last < 1){
$last = 1;
}
$pagenum = 1;
if(isset($_GET['pn'])){
$pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']);
}
if ($pagenum < 1) {
$pagenum = 1;
} else if ($pagenum > $last) {
$pagenum = $last;
}
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
$sql = "SELECT id, firstname, lastname, datemade FROM testimonials WHERE approved='1' ORDER BY id DESC $limit";
$query = mysqli_query($db_conx, $sql);
$textline1 = "Testimonials (<b>$rows</b>)";
$textline2 = "Page <b>$pagenum</b> of <b>$last</b>";
$paginationCtrls = '';
if($last != 1){
if ($pagenum > 1) {
$previous = $pagenum - 1;
$paginationCtrls .= 'Previous ';
for($i = $pagenum-4; $i < $pagenum; $i++){
if($i > 0){
$paginationCtrls .= ''.$i.' ';
}
}
}
$paginationCtrls .= ''.$pagenum.' ';
for($i = $pagenum+1; $i <= $last; $i++){
$paginationCtrls .= ''.$i.' ';
if($i >= $pagenum+4){
break;
}
}
if ($pagenum != $last) {
$next = $pagenum + 1;
$paginationCtrls .= ' Next ';
}
}
$list = '';
while($row = mysqli_fetch_array($query, MYSQLI_ASSOC)){
$id = $row["id"];
$firstname = $row["firstname"];
$lastname = $row["lastname"];
$datemade = $row["datemade"];
$datemade = strftime("%b %d, %Y", strtotime($datemade));
$list .= '<p>'.$firstname.' '.$lastname.' Testimonial - Click the link to view this testimonial<br>Written '.$datemade.'</p>';
}
mysqli_close($db_conx);
?>
<!DOCTYPE html>
<html>
<head>
<style type="text/css">
body{ font-family:"Trebuchet MS", Arial, Helvetica, sans-serif;}
div#pagination_controls{font-size:21px;}
div#pagination_controls > a{ color:#06F; }
div#pagination_controls > a:visited{ color:#06F; }
</style>
</head>
<body>
<div>
<h2><?php echo $textline1; ?> Paged</h2>
<p><?php echo $textline2; ?></p>
<p><?php echo $list; ?></p>
<div id="pagination_controls"><?php echo $paginationCtrls; ?></div>
</div>
</body>
</html>

PHP Pagination issue mysql and php showing same data on all pages

I am having issues with some pagination with data i get from a MySQL database in PHP.
My code is below. Basically what happens is it creates the right amount of pages however each page shows the same data and doesn't even show only 5 rows per page.
I'm really stuck. This is my first time trying pagination. Any help would be greatly appreciated.
$pagenum = $_GET['pagenum'];
if (!(isset($pagenum)))
{
$pagenum = 1;
} else
{
$pagenum = $_GET['pagenum'];
}
//Count the number of results.
$data = mysql_query("SELECT * FROM `articles` WHERE `content` = '' AND `requestedby` != '$id'") or die(mysql_error());
$rows = mysql_num_rows($data);
//Set the number of results to be displayed per page.
$page_rows = 5;
//This tells us the page number of our last page
$last = ceil($rows/$page_rows);
//this makes sure the page number isn't below one, or more than our maximum pages
if ($pagenum < 1)
{
$pagenum = 1;
} elseif ($pagenum > $last)
{
$pagenum = $last;
}
//This sets the range to display in our query
$max = 'LIMIT ' . ($pagenum - 1) * $page_rows .',' .$page_rows;
//This is the query again, the same one... the only difference is we add $max into it.
$data_p = mysql_query("SELECT * FROM `articles` WHERE `content` = '' AND `requestedby` != '$id' '$max'") or die(mysql_error());
//Work out writers earnings based on prices.
//100 Words - $1.25
//300 Words - $2.50
//500 Words - $4.00
//700 Words - $5.50
//1000 Words - $8.00
$_100earnings = "0.65";
$_300earnings = "1.25";
$_500earnings = "2.50";
$_700earnings = "3.00";
$_1000earnings = "5.00";
?>
<!-- main -->
<div id="main">
<center><h2>Write Articles</h2></center>
<br />Available Projects:
<table border="1">
<tr>
<td>Title:</td>
<td>Length:</td>
<td>Writers Earnings:</td>
</tr>
<?php
//This is where you display your query results
while($info = mysql_fetch_array($data_p))
{
echo "<tr>";
echo "<td>" . $info['keywords'] . "</td>";
echo "<td>" . $info['length'] . "</td>";
switch ($info['length'])
{
case 100:
$writersearnings = $_100earnings;
break;
case 300:
$writersearnings = $_300earnings;
break;
case 500:
$writersearnings = $_500earnings;
break;
case 700:
$writersearnings = $_700earnings;
break;
case 1000:
$writersearnings = $_1000earnings;
break;
}
echo "<td>$" . $writersearnings . "</td>";
//echo $info['Name'];
echo "</tr>";
}
?>
</table>
<br /><br />
<?php
// This shows the user what page they are on, and the total number of pages
echo " --Page $pagenum of $last-- <p>";
// First we check if we are on page one. If we are then we don't need a link to the previous page or the first page so we do nothing. If we aren't then we generate links to the first page, and to the previous page.
if ($pagenum == 1)
{
} else
{
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> ";
echo " ";
$previous = $pagenum - 1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> ";
}
//just a spacer
echo " ---- ";
//This does the same as above, only checking if we are on the last page, and then generating the Next and Last links
if ($pagenum == $last)
{
} else
{
$next = $pagenum + 1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last ->></a> ";
}
use this code, remove ' around $max in query, when you add ' around $max the query becomes select.... from.... where..... 'LIMIT.....' and it fails the query.
$data_p = mysql_query("SELECT * FROM `articles` WHERE `content` = '' AND `requestedby` != '$id' $max") or die(mysql_error());
You need to specify LIMIT in your query LIMIT offset,count
$data_p = mysql_query("SELECT * FROMarticlesWHEREcontent= '' ANDrequestedby!= '$id' '$max'") or die(mysql_error());
Remove the ' quotes from '$max'
$data_p = mysql_query("SELECT * FROM articles WHERE content= '' AND requestedby!= '".$id."' ".$max) or die(mysql_error());

pagination error there is no records in page two

i searched about php pagination and i found a site who explains the codes very well, my question is about the codes, everytime i click "next" link, page 2 has to results. i dont understand why page 2 has no results. here is the code:
<?php
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("kp_and_harang") or die(mysql_error());
if (!(isset($pagenum)))
{
$pagenum = 1;
}
$data = mysql_query("SELECT * FROM students") or die(mysql_error());
$rows = mysql_num_rows($data);
$page_rows = 4;
$last = ceil($rows/$page_rows);
if ($pagenum < 1)
{
$pagenum = 1;
}
elseif ($pagenum > $last)
{
$pagenum = $last;
}
$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows;
$data_p = mysql_query("SELECT * FROM students $max") or die(mysql_error());
while($info = mysql_fetch_array( $data_p ))
{
Print $info['surname'];
echo "<br>";
}
echo "<p>";
echo " --Page $pagenum of $last-- <p>";
if ($pagenum == 1)
{
}
else
{
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> ";
echo " ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> ";
}
echo " ---- ";
if ($pagenum == $last)
{
}
else {
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last ->></a> ";
}
?>
First of all, unless absolutely necessary it's not advisable to use SELECT * you should use specific fields. Right now you're making a full search on the same table twice. Select one field only if you want to count the rows only.
You should also use PDO functions instead of mysql_* which are deprecated.
Are you sure there should be a second page? How many records are there in students table?
To debug your code dump query results and check the "SELECT * FROM students $max" query.
You put the page number in the url, but you never retrieve it from the url?
I changed this part:
if (!(isset($pagenum)))
{
$pagenum = 1;
}
to this:
if (!(isset($_GET['pagenum'])))
{
$pagenum = 1;
} else {
$pagenum = $_GET['pagenum'];
}
And it seems to work perfectly.
EDIT
To just get the total count of rows you don't have to fetch everything. You can just do the following:
$result = mysql_query("SELECT count(*) FROM students") or die(mysql_error());
$rows = mysql_fetch_row($result);

PHP paging, viewing a certain page first

This is my script for the paging on my site when the user clicks on a league.
The league is then echoed to the screen, and if the league is over 3 rows then it splits it up in to several pages.
What I am doing after is depending on where the user is in the league (the SQL query is using ORDER BY the total points column in the table), e.g if the user is on page one of the league table then for it to display that page first, but if the user is on page 3 of the league table then for that page to displayed first.
Does anyone know a way in order for me to achieve this?
//Recently updated from answer
$sql="SELECT members.username, members.total_points FROM members, members_leagues WHERE members.username = members_leagues.username AND
members_leagues.sub_league = '$chosenleague' ORDER BY members.total_points DESC";
$result=mysql_query($sql);
$i = 0;
$found = false;
$team_position = 0;
while (!$found && $row = mysql_fetch_row($result)){
if ($row[username] == $_SESSION[username]) {
$team_position = $i;
$found = true;
}
$i++;
}
$rowsPerPage = 3;
$pageNum = ceil($i/$rowsPerPage);
//end of recently updated
if(isset($_GET['page']))
$pageNum = $_GET['page'];
$offset = ($pageNum - 1) * $rowsPerPage;
$counter = $offset + 1;
$query = " SELECT members.username, members.teamname, members.total_points, FROM members, members_leagues WHERE members.username = members_leagues.username AND members_leagues.sub_league = '$chosenleague' ORDER BY members.total_points DESC " . " LIMIT $offset, $rowsPerPage";
$result = mysql_query($query) or die('Error, query failed');
echo "<h3 style=\"color:red;\">$chosenleague</h3>";
echo "<table>";
echo "<tr><th>Position</th>";
echo "<th>Team</th>";
echo "<th>Points/Overall</th>";
echo "<th>Points/Last Race</th>";
echo "<th>Team Setup</th></tr>";
while($row = mysql_fetch_array($result))
{
if($row[username] == $_SESSION[username])
echo "<tr style=\"color:red;\"><td>";
else
echo "<tr><td>";
echo $counter;
echo "</td><td>";
echo $row[teamname];
echo "</td><td>";
echo $row[total_points];
echo "</td><td>";
echo "</td><td>";
echo "</td></tr>";
$counter++;
}
echo "</table>";
$query = "SELECT COUNT(members.username) AS numrows FROM members, members_leagues WHERE members.username = members_leagues.username
AND members_leagues.sub_league = '$chosenleague'";
$result = mysql_query($query) or die('Error, query failed');
$row = mysql_fetch_array($result, MYSQL_ASSOC);
$numrows = $row['numrows'];
$maxPage = ceil($numrows/$rowsPerPage);
$self = $_SERVER['PHP_SELF'];
$nav = '';
if ($pageNum > 1)
{
$page = $pageNum - 1;
$prev = " << Prev ";
$first = " First ";
}
else
{
$prev = '';
$first = '';
}
if ($pageNum < $maxPage)
{
$page = $pageNum + 1;
$next = " Next >> ";
$last = " Last ";
}
else
{
$next = '';
$last = '';
}
echo "<div id=\"pagenum\">Page $pageNum of $maxPage ". $first . $last . $prev . $next ."</div>";
You can do it via mysql or php:
With PHP:
Found the position of the requested record in the array, then calculate the page you have to extract and execute the corresponding query. Something like.
$i = 0;
$found = false;
$team_position = 0;
while (!$found && $row = mysql_fetch_row) {
if ($row['team'] == 'team_your_searching_for') {
$team_position = $i;
$found = true;
}
$i++;
}
//calculate $top and $bottom
...
$sql = "SELECT * FROM members LIMIT $top, $bottom;";
...
With MySQL:
You can create a query that generates an autoincrement value and another that selects from the other's result. I mean
-- get the the selected member's position
SELECT team, pos FROM (SELECT team, points, #position = #position + 1 AS pos FROM members ORDER BY points) WHERE team = #the_team_your_searching_for;
-- get the nr of members
SELECT COUNT(*) FROM members;
...
-- calculate the page you wanna extract (#top, #bottom), and extract it
SELECT * FROM members LIMIT #top, #bottom;

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