I have a problem with a string to convert in number. I am not good with this elements !\d+!
I used that but the apporach is not correct.
Thank you.
preg_match_all('!\d+!', $product_price[$i], $matches);
$price_extracted = (float)implode('.', $matches[0]);
$item['normal_price'] = $price_extracted;
if ($item['normal_price'] > 800) ......
I have this result
1 299,99 $ (orginal) is converted in 1.2999 and must be 1299.99
549,99 $ (orginal) is converted in 549.99 and must be 549.99
44,99 $ (orginal) is converted in 44.99 and must be 44.99
The problem with your approach is, that you put the digits that are not separated by anything into an array.
This means that with the first string that you provided, where the thousand dollars is seperated by a whitespace is being registered as one of these matches.
preg_match_all('!\d+!', '1 299,99 $', $matches) -> returns an array as follows:
$matches[0] = 1
$matches[1] = 299
$matches[2] = 99
If you take my approach though and first replace all whitespaces by nothing and then split the numbers into the array...:
preg_match_all('!\d+!', preg_replace('/\s/', '', '1 299,99 $'), $matches) -> returns following array:
$matches[0] = 1299
$matches[1] = 99
after that you can still implode them:
$price_exctracted = (float)implode(".", $matches);
EDIT
A little explanation about preg_replace, preg_match_all and regex:
The regex '!\d+!' (I don't actually know why there would be '!' instead of '/' but if it works...) searches for digits (\d). The "+" refers to "one or more". So the line
preg_match_all('!\d+!', 'someString', $myArray)
could be translated into english as follows:
Find all occurances of digits, be it one or more,
and put these occurances separated into one index of $myArray.
The second regex used in my solution, '/\s/' , is used to search for whitespaces. The "preg_replace"-function is an easy "find and replace" function concluding in:
preg_replace('/\s/', '', 'someString')
translated to english:
Find all occurances of whitespaces and replace them with nothing in 'someString'
For reference:
preg_match_all
preg_replace
regex cheat sheet
Conditions can be checked on:
PHP Live Regex
Related
I am trying to search this coincidence in a string:
1. I need to take only numbers after the chracter '#' as long as this coincidence has not spaces, for example:
String = 'This is a test #VVC345RR, text, and more text 12345';
I want to take only this from my string -> 345.
My example:
$s = '\"access_token=103782364732640461|2. myemail#domain1.com ZmElnDTiZlkgXbT8e3 #DD234 4Jrw__.3600.1281891600-10000186237005';
$matches = array();
$s = preg_match('/#([0-9]+)/', $s, $matches);
print_r($matches);
This only works when I have one # and numbers.
Thanks!
Maybe:
#\D*\K(\d+)
Accomplishes what you want?
This will look for an #, any non-numbers, and then capture the numbers. The \K ignores the early match.
https://regex101.com/r/gNTccx/1/
I'm unclear what you mean by has not spaces, there are no spaces in the example string.
I have a question. I need to add a + before every word and see all between quotes as one word.
A have this code
preg_replace("/\w+/", '+\0', $string);
which results in this
+test +demo "+bla +bla2"
But I need
+test +demo +"bla bla2"
Can someone help me :)
And is it possible to not add a + if there is already one? So you don't get ++test
Thanks!
Maybe you can use this regex:
$string = '+test demo between "double quotes" and between \'single quotes\' test';
$result = preg_replace('/\b(?<!\+)\w+|["|\'].+?["|\']/', '+$0', $string);
var_dump($result);
// which will result in:
string '+test +demo +between +"double quotes" +and +between +'single quotes' +test' (length=74)
I've used a 'negative lookbehind' to check for the '+'.
Regex lookahead, lookbehind and atomic groups
I can't test this but could you try it and let me know how it goes?
First the regex: choose from either, a series of letters which may or may not be preceded by a '+', or, a quotation, followed by any number of letters or spaces, which may be preceded by a '+' followed by a quotation.
I would hope this matches all your examples.
We then get all the matches of the regex in your string, store them in the variable "$matches" which is an array. We then loop through this array testing if there is a '+' as the first character. If there is, do nothing, otherwise add one.
We then implode the array into a string, separating the elements by a space.
Note: I believe $matches in created when given as a parameter to preg_match.
$regex = '/[((\+)?[a-zA-z]+)(\"(\+)?[a-zA-Z ]+\")]/';
preg_match($regex, $string, $matches);
foreach($matches as $match)
{
if(substr($match, 0, 1) != "+") $match = "+" + $match;
}
$result = implode($matches, " ");
I have a string with some numbers and text and I'm trying to split the string at the first non-numeric character.
For Example, I have a few strings like
$value = '150px';
$value = '50em';
$value = '25%';
I've been trying to split the string using preg_split and a little regex.
$value_split = preg_split( '/[a-zA-Z]/' , $fd['yks-mc-form-padding'] );
I'm able to get the first part of the string using $value_split[0], for example I can store 150, or 50 or 25. I need to return the second part of the string as well (px, em or %).
How can I split the string using preg_split or something similar to return both parts of the array??
Thanks!
If you want to use regex and you haven't already, you should play with RegExr.
To do what you're wanting with regex, assuming all the strings will be all numeric together, followed by all non-numeric, you could do:
$matches = array();
preg_match('/([0-9]+)([^0-9]+)/',$value,$matches);
Then $matches[1] will be the numeric part and $matches[2] will be the rest
To break it down,
[0-9] matches any numeric character, so [0-9]+ matches 1 or more numeric characters in a row, so per the docs $matches[1] will have the (numeric) text matched in by the first set of parentheses
and [^0-9] matches any non-numeric character, so [^0-9]+ matches 1 or more non-numeric characters in a row and fills $matches[2] because it's in the 2nd set of parentheses
By preg_split() you cannot achieve what are you trying to. It will delete the part of your string which separates the whole string (in this case it will be separated by character [a-zA-Z]). Use preg_match() (or preg_match_all()) function.
You can use this pattern:
/([0-9]+)([a-zA-Z%]+)/
See demo.
Use the PREG_SPLIT_OFFSET_CAPTURE flag - it will cause an array to be returned, with item [0] being the string matched, and item [1] its starting position in the original string.
You can then use that info to extract the rest of the string by using ordinary sub-string functionality.
Something along the lines of:
$values_split = preg_split( '/[a-zA-Z]/' , $fd['yks-mc-form-padding'] );
$position = $values_split[0][1]
$length = $values_split[0][0]
$startPos = $position + $length
$numToGet = lenght($input) - $startPos
$remainder = substr($inline, startPos, $numToGet)
I'm looking for an way to parse a substring using PHP, and have come across preg_match however I can't seem to work out the rule that I need.
I am parsing a web page and need to grab a numeric value from the string, the string is like this
producturl.php?id=736375493?=tm
I need to be able to obtain this part of the string:
736375493
$matches = array();
preg_match('/id=([0-9]+)\?/', $url, $matches);
This is safe for if the format changes. slandau's answer won't work if you ever have any other numbers in the URL.
php.net/preg-match
<?php
$string = "producturl.php?id=736375493?=tm";
preg_match('~id=(\d+)~', $string, $m );
var_dump($m[1]); // $m[1] is your string
?>
$string = "producturl.php?id=736375493?=tm";
$number = preg_replace("/[^0-9]/", '', $string);
Unfortunately, you have a malformed url query string, so a regex technique is most appropriate. See what I mean.
There is no need for capture groups. Just match id= then forget those characters with \K, then isolate the following one or more digital characters.
Code (Demo)
$str = 'producturl.php?id=736375493?=tm';
echo preg_match('~id=\K\d+~', $str, $out) ? $out[0] : 'no match';
Output:
736375493
For completeness, there 8s another way to scan the formatted string and explicitly return an int-typed value. (Demo)
var_dump(
sscanf($str, '%*[^?]?id=%d')[0]
);
The %*[^?] means: greedily match one or more non-question mark characters, but do not capture the substring. The remainder of the format parameter matches the literal sequence ?id=, then greedily captures one or more numbers. The returned value will be cast as an integer because of the %d placeholder.
I want to split a string on several chars (being +, ~, > and #, but I want those chars to be part of the returned parts.
I tried:
$parts = preg_split('/\+|>|~|#/', $input, PREG_SPLIT_DELIM_CAPTURE);
The result is only 2 parts where there should be 5 and the split-char isn't part of part [1].
I also tried:
$parts = preg_split('/\+|>|~|#/', $input, PREG_SPLIT_OFFSET_CAPTURE);
The result is then 1 part too few (4 instead of 5) and the last part contains a split-char.
Without flags in preg_split, the result is almost perfect (as many parts as there should be) but all the split-chars are gone.
Example:
$input = 'oele>boele#4 + key:type:id + *~the end'; // spaces should be ignored
$output /* should be: */
array( 'oele', '>boele', ' #4 ', '+ key:type:id ', '+ *', '~the end' );
Is there a spl function or flag to do this or do I have to make one myself =(
$parts = preg_split('/(?=[+>~#])/', $input);
See it
Since you want to have the delimiters to be part of the next split piece, your split point is right before the delimiter and this can be easily done using positive look ahead.
(?= : Start of positive lookahead
[+>~#] : character class to match any of your delimiters.
) : End of look ahead assertion.
Effectively you are asking preg_split to split the input string at points just before delimiters.
You're missing an assignment for the limit parameter which is why it's returning less than you expected, try:
$parts = preg_split('/\+|>|~|#/', $input, -1, PREG_SPLIT_OFFSET_CAPTURE);
well i had the same problem in the past. You have to parenthese your regexp with brackets and then it hopefully works
$parts = preg_split('/(\+|>|~|#)/', $input, PREG_SPLIT_OFFSET_CAPTURE);
and here is it explained: http://www.php.net/manual/en/function.preg-split.php#94238
Ben is correct.
Just to add to his answer, PREG_SPLIT_DELIM_CAPTURE is a constant with value of 2 so you get 2 splits, similarly PREG_SPLIT_OFFSET_CAPTURE has a value of 4.