I want my PHP to create ONE table, but it creates SEVERAL - php

Question

I need to create a table via php with data from my mysql server. I've managed to establish a connection, and I can create a table, but my problem is that it creates a table for each of the rows, whereas I want one unified. This is my code:
$sql = 'SELECT navn, institution, klip FROM parkeringsdata';
mysqli_select_db($conn , 'parkeringsdb');
$retval = mysqli_query( $conn , $sql );
echo "<br><br><br>";
if(! $retval ) {
die('Could not get data: ' . mysqli_error());
}
while($row = mysqli_fetch_array($retval, MYSQLI_ASSOC)) {
echo "<table class='content info'>
<tr>
<td>Navn</td>
<td>Institution</td>
<td>Klip</td>
<td>Rediger</td>
<td>Slet</td>
</tr>
<tr>
<td>".$row["navn"]."</td>
<td>".$row["institution"]."</td>
<td>".$row["klip"]."</td>
<td><button type='button'>Rediger</button></td>
<td><button type='button'>Slet</button></td>
</tr></table><br>";
}
echo "Fetched data successfully\n";
mysqli_close($conn);
EDIT: Thanks for all the quick responses, it's solved now and I see where I made it a rookie mistake. It's for a school assignment and we'd been wracking our brains here :)

Answer 1

You'll want to extract the "", "" and your table-header definition out of the for loop, so it will only be executed once.
And: Creating tables this way is easy to do, but leads to error-prone & difficult to maintain code.
It's okay to learn it step by step.
But most likely you'll want to switch to a templating engine (on client or server side, your&your applications choice) sooner or later.

Answer 2

$table = "<table class='content info'>";
while($row = mysqli_fetch_array($retval, MYSQLI_ASSOC)) {
$table .= "
<tr>
<td>Navn</td>
<td>Institution</td>
<td>Klip</td>
<td>Rediger</td>
<td>Slet</td>
</tr>
<tr>
<td>".$row["navn"]."</td>
<td>".$row["institution"]."</td>
<td>".$row["klip"]."</td>
<td><button type='button'>Rediger</button></td>
<td><button type='button'>Slet</button></td>
</tr>";
}
$table .= "</table><br>";
You have table start and end tags inside foreach loop.

Answer 3

Echo table outside the while loop
$sql = 'SELECT navn, institution, klip FROM parkeringsdata';
mysqli_select_db($conn , 'parkeringsdb');
$retval = mysqli_query( $conn , $sql );
echo "<br><br><br>";
if(! $retval ) {
die('Could not get data: ' . mysqli_error());
}
echo "<table class='content info'>";
while($row = mysqli_fetch_array($retval, MYSQLI_ASSOC)) {
echo "<tr>
<td>Navn</td>
<td>Institution</td>
<td>Klip</td>
<td>Rediger</td>
<td>Slet</td>
</tr>
<tr>
<td>".$row["navn"]."</td>
<td>".$row["institution"]."</td>
<td>".$row["klip"]."</td>
<td><button type='button'>Rediger</button></td>
<td><button type='button'>Slet</button></td>
</tr>";
}
echo "</table><br>";
echo "Fetched data successfully\n";
mysqli_close($conn);