PHP get index into new array - php

Question

I have a json array like below. I need to get the index into a new array, how is this possible? Arrays are my weakness for some reason just cant grasp them. I can easily get id value, but cannot get the index (e.g 11111111). Any help would be appreciated.
Update please see the revised, my fault for not including the full multi dimensional array.
Below only outputs one result where I need all results.
<?php
$json = '[{
"11111111": {
"id": "val_somevalue5555",
"customer": {
"32312": {
"name": "jane doe"
}
}
},
"2222222": {
"id": "val_somevalue25",
"customer": {
"32312234": {
"name": "jane doe"
}
}
}
}]';
$jsonarr = json_decode($json, true);
$newarr = [];
foreach($jsonarr as $value)
{
$key = key($value);
$newarr[] = ['key' => $key, 'id' => $value[$key]['id']];
}
var_dump($newarr);
expected looped output
key 11111111
id val_somevalue5555
... looped.

Answer 1

You can create an array of the keys of an existing array using the array_keys() function
http://php.net/manual/en/function.array-keys.php
If you don't want the keys in a separate array, and instead just want to access them directly, when you are doing a 'foreach' loop of an array, you can choose to assign a variable to the current key by doing
foreach($jsonarr as $key => $value){...}
Because your original array is actually multidimensional (each $key has a $value that is also stored as an array of "id": "value") - this means taking one more step to get the value of key 'id':
foreach($jsonarr as $key => $value){
$newarray[] = ['key' => $key, 'id' => $value['id'];
}

Answer 2

you can use array_keys() or key() with a foreach loop for this(DEMO):
$newarr = [];
foreach($jsonarr as $value)
{
//$key = array_keys($value)[0];
$key = key($value);
$newarr[] = ['key' => $key, 'id' => $value[$key]['id']];
}
var_dump($newarr);
Output:
array(2) {
[0]=>
array(2) {
["key"]=>
int(11111111)
["id"]=>
string(17) "val_somevalue5555"
}
[1]=>
array(2) {
["key"]=>
int(2222222)
["id"]=>
string(15) "val_somevalue25"
}
}
Edit: With the updated json, you can use the following way, using 2 foreach loops (DEMO):
$newarr = [];
foreach($jsonarr as $json)
{
foreach($json as $key => $value)
{
$newarr[] = ['key' => $key, 'id' => $value['id']];
}
}

Answer 3

PHP supports a slightly different foreach syntax that extracts both the array key and the array value:
foreach ( $jsonarr as $key => $value ) {
$newarr[] = ['key' => $key, 'id' => $value];
}
Use this if you need the key ("11111111" and "2222222" in your example).

Answer 4

<?php
$json = '[{
"11111111": {
"id": "val_somevalue5555"
}
},
{
"2222222": {
"id": "val_somevalue25"
}
}
]';
$jsonarr = json_decode($json, true);
$newarr = [];
foreach($jsonarr as $key => $value) {
$newarr[] = ['key' => key($value), 'id' => current($value)['id']];
}
foreach($newarr as $key) {
echo 'key '.$key['key'] . PHP_EOL;
echo 'id '.$key['id'] . PHP_EOL;
}

Answer 5

If you remove what looks like embedded components in the $json string (otherwise it won't parse) then var_export the output of json_decode() you'll get this:
array (
0 => array (
11111111 => array (
'id' => 'val_somevalue5555',
),
),
1 => array (
2222222 => array (
'id' => 'val_somevalue25',
),
),
)
You have a double-nested array, hence...
foreach ($jsonarr as $obj) {
foreach ($obj as $name=>$value) {
print "$name = $value[id]\n";
break;
}
}
or you can reference the elements directly:
print $jsonarr[0]['11111111']['id'];

Answer 6

First, you are not accessing the deep enough before iterating.
If you call var_export($jsonarr); you will see:
array ( // an indexed array of subarrays
0 =>
array ( // an associative array of subarrays, access via [0] syntax (or a foreach loop that only iterates once)
11111111 => // this is the subarray's key that you want
array (
'id' => 'val_somevalue5555', // this is the value you seek from the id element of 1111111's subarray
'customer' =>
array (
32312 =>
array (
'name' => 'jane doe',
),
),
),
2222222 => // this is the subarray's key that you want
array (
'id' => 'val_somevalue25', // this is the value you seek from the id element of 2222222's subarray
'customer' =>
array (
32312234 =>
array (
'name' => 'jane doe',
),
),
),
),
)
Code: (Demo)
$jsonarr = json_decode($json, true);
$result=[];
// vvvv-avoid a function call (key()) on each iteration by declaring here
foreach($jsonarr[0] as $key=>$subarray){
// ^^^-drill down into the first level (use another foreach loop if there may be more than one)
$result[]=['key'=>$key,'id'=>$subarray['id']];
}
var_export($result);
Output:
array (
0 =>
array (
'key' => 11111111,
'id' => 'val_somevalue5555',
),
1 =>
array (
'key' => 2222222,
'id' => 'val_somevalue25',
),
)
p.s. If $jsonarr has more than one element in its first level, you should use a foreach() loop like this:
foreach($jsonarr as $array1){
foreach($array1 as $key=>$array2){
$result[]=['key'=>$key,'id'=>$array2['id']];
}
}