MongoDB find() in multidimensional array and $unset [duplicate] - php

Question

Here is array structure
contact: {
phone: [
{
number: "[phone]",
place: "New Jersey",
createdAt: ""
}
{
number: "[phone]",
place: "Houston",
createdAt: ""
}
]
}
Here I only know the mongo id(_id) and phone number([phone]) and I need to remove that whole corresponding array element from document. i.e zero indexed element in phone array is matched with phone number and need to remove the corresponding array element.
contact: {
phone: [
{
number: "[phone]",
place: "Houston",
createdAt: ""
}
]
}
I tried with following update method
collection.update(
{ _id: id, 'contact.phone': '[phone]' },
{ $unset: { 'contact.phone.$.number': '[phone]'} }
);
But it removes number: [phone] from inner array object, not zero indexed element in phone array. Tried with pull also without a success.
How to remove the array element in mongodb?

Answer 1

Try the following query:
collection.update(
{ _id: id },
{ $pull: { 'contact.phone': { number: '[phone]' } } }
);
It will find document with the given _id and remove the phone [phone] from its contact.phone array.
You can use $unset to unset the value in the array (set it to null), but not to remove it completely.

Answer 2

You can simply use $pull to remove a sub-document.
The $pull operator removes from an existing array all instances of a value or values that match a specified condition.
Collection.update({
_id: parentDocumentId
}, {
$pull: {
subDocument: {
_id: SubDocumentId
}
}
});
This will find your parent document against given ID and then will remove the element from subDocument which matched the given criteria.
Read more about pull here.

Answer 3

In Mongoose:
from the document:
To remove a document from a subdocument array we may pass an object
with a matching _id.
contact.phone.pull({ _id: itemId }) // remove
contact.phone.pull(itemId); // this also works
See Leonid Beschastny's answer for the correct answer.

Answer 4

To remove all array elements irrespective of any given id, use this:
collection.update(
{ },
{ $pull: { 'contact.phone': { number: '[phone]' } } }
);

Answer 5

To remove all matching array elements from a specific document:
collection.update(
{ _id: id },
{ $pull: { 'contact.phone': { number: '[phone]' } } }
);
To remove all matching array elements from all documents:
collection.updateMany(
{ },
{ $pull: { 'contact.phone': { number: '[phone]' } } }
);

Answer 6

Given the following document in the profiles collection:
{ _id: 1, votes: [ 3, 5, 6, 7, 7, 8 ] }
The following operation will remove all items from the votes array that are greater than or equal to ($gte) 6:
db.profiles.update( { _id: 1 }, { $pull: { votes: { $gte: 6 } } } )
After the update operation, the document only has values less than 6:
{ _id: 1, votes: [ 3, 5 ] }
If you multiple items the same value, you should use $pullAll instead of $pull.
In the question having a multiple contact numbers the same use this:
collection.update(
{ _id: id },
{ $pullAll: { 'contact.phone': { number: '[phone]' } } }
);
it will delete every item that matches that number. in contact phone
Try reading the manual.