I have a url. I want to parse url. I don't want to get last two value. How can I do?
$str="first-second-11.1268955-15.542383564";
As I wanted
$str="first-second";
I used this code. But I don't want to get - from last value
$arr = explode("-", $str);
for ($a = 0; $a < count($arr) - 2; $a++) {
$reqPage .= $arr[$a] . "-";
}
You can use regular expressions too.Those are patterns used to match character combinations in strings.:
W*((?i)first-second(?-i))\W*
Use the 3rd param of explode() called limit:
$str="first-second-11.1268955-15.542383564";
$arr = explode("-", $str, -2);
$reqPage = implode($arr, "-"); // contains "first-second"
Regex is the fastest way for the string manipulations. Try this.
$str="first-second-11.1268955-15.542383564";
preg_match('/^[a-z]*-{1}[a-z]*/i', $str, $matches);
$match = count($matches) > 0 ? $matches[0] : '';
echo $match;
Related
I've spent my last 4 hours figuring out how to ... I got to ask for your help now.
I'm trying to extract from a text multiple substring match my starting_words_array and ending_words_array.
$str = "Do you see that ? Indeed, I can see that, as well as this." ;
$starting_words_array = array('do','I');
$ending_words_array = array('?',',');
expected output : array ([0] => 'Do you see that ?' [1] => 'I can see that,')
I manage to write a first function that can find the first substring matching one of both arrays items. But i'm not able to find how to loop it in order to get all the substring matching my requirement.
function SearchString($str, $starting_words_array, $ending_words_array ) {
forEach($starting_words_array as $test) {
$pos = strpos($str, $test);
if ($pos===false) continue;
$found = [];
forEach($ending_words_array as $test2) {
$posStart = $pos+strlen($test);
$pos2 = strpos($str, $test2, $posStart);
$found[] = ($pos2!==false) ? $pos2 : INF;
}
$min = min($found);
if ($min !== INF)
return substr($str,$pos,$min-$pos) .$str[$min];
}
return '';
}
Do you guys have any idea about how to achieve such thing ?
I use preg_match for my solution. However, the start and end strings must be escaped with preg_quote. Without that, the solution will be wrong.
function searchString($str, $starting_words_array, $ending_words_array ) {
$resArr = [];
forEach($starting_words_array as $i => $start) {
$end = $ending_words_array[$i] ?? "";
$regEx = '~'.preg_quote($start,"~").".*".preg_quote($end,"~").'~iu';
if(preg_match_all($regEx,$str,$match)){
$resArr[] = $match[0];
}
}
return $resArr;
}
The result is what the questioner expects.
If the expressions can occur more than once, preg_match_all must also be used. The regex must be modify.
function searchString($str, $starting_words_array, $ending_words_array ) {
$resArr = [];
forEach($starting_words_array as $i => $start) {
$end = $ending_words_array[$i] ?? "";
$regEx = '~'.preg_quote($start,"~").".*?".preg_quote($end,"~").'~iu';
if(preg_match_all($regEx,$str,$match)){
$resArr = array_merge($resArr,$match[0]);
}
}
return $resArr;
}
The resut for the second variant:
array (
0 => "Do you see that ?",
1 => "Indeed,",
2 => "I can see that,",
)
I would definitely use regex and preg_match_all(). I won't give you a full working code example here but I will outline the necessary steps.
First, build a regex from your start-end-pairs like that:
$parts = array_map(
function($start, $end) {
return $start . '.+' . $end;
},
$starting_words_array,
$ending_words_array
);
$regex = '/' . join('|', $parts) . '/i';
The /i part means case insensitive search. Some characters like the ? have a special purpose in regex, so you need to extend above function in order to escape it properly.
You can test your final regex here
Then use preg_match_all() to extract your substrings:
preg_match_all($regex, $str, $matches); // $matches is passed by reference, no need to declare it first
print_r($matches);
The exact structure of your $matches array will be slightly different from what you asked for but you will be able to extract your desired data from it
Benni answer is best way to go - but let just point out the problem in your code if you want to fix those:
strpos is not case sensitive and find also part of words so you need to changes your $starting_words_array = array('do','I'); to $starting_words_array = array('Do','I ');
When finding a substring you use return which exit the function so you want find any other substring. In order to fix that you can define $res = []; at the beginning of the function and replace return substr($str,$pos,... with $res[] = substr($str,$pos,... and at the end return the $res var.
You can see example in 3v4l - in that example you get the output you wanted
I have the following string...
$string = "True is True (5-7 years)";
what I want is to get - TiT(5-7 years)
I have tried the following code but no luck...
$string = "True is True (5-7 years)";
$explodedString = explode(" ",$string);
for($i = 0; $i < 4; $i++){
$tempString = substr($explodedString[$i], 0, 1);
$finalString .= $tempString;
}
In short, I need the first three words of its initials and the remaining in bracket is as it is like this.... TiT(5-7 years). how?
This a good case for using regular expressions:
$str = 'True is True (5-7 years)';
preg_match_all('~\([^()]*\)|\b\w~', $str, $matches);
echo implode("", $matches[0]); // TiT(5-7 years)
Regex breakdown:
\([^()]*\) Match anything inside parentheses including themselves
| Or
\b\w Match first word character from a word
Your loop is going one element too far. If you want the first letter of the first 3 words, it should be $i < 3.
Then you should use array_slice() and implode() to concatenate the rest of the array.
for ($i = 0; $i < 3; $i++) {
$finalString .= $explodedString[$i][0];
}
$finalString .= implode(' ', array_slice($explodedString, 3));
DEMO
$string = "True is True (5-7 years)";
$new_string = preg_replace('/^([a-z])[a-z]+ ([a-z])[a-z]+ ([a-z])[a-z]+ (\(.+\))$/i', '$1$2$3$4', $string);
First of all.
Create an empty variable. That will be your final result
$result="";
Then youse foreach to loop your explode string.
At every part chech the first character.
If it's not ( add the first char onto the result variable.
else add the whole array element onto the result variable
foreach(explodedString as $t){
If($t[0] !="("){$result.=$t[0];} else{$result.=$t;}
}
At the end of the loop you will get what you wanted
echo $result;
How can I format an arbitrary string according to a flexible pattern? The only solution I came up with is using regular expressions, but then I need 2 "patterns" (one for the search and one for the output).
Example:
$str = '123ABC5678";
Desired output: 12.3AB-C5-67.8
I would like to use a pattern in a variable (one that a user can easily define without knowledge of regular expressions) It could look like this:
$pattern = '%%.%%%-%%-%%.%';
So the user would just have to use 2 different characters (% and .)
A solution with regex would look like this:
$str = '123ABC5678';
$pattern_src = '#(.{2})(.{3})(.{2})(.{2})(.{1})#';
$pattern_rpl = "$1.$2-$3-$4.$5";
$res = preg_replace($pattern_src, $pattern_rpl, $str);
//$res eq 12.3AB-C5-67.8
Way too complicated since the user would need to define $pattern_src and $pattern_rpl. If the string could vary in length, it would be even more complex to explain.
Yes, I could write a function/parser that builds the required regular expressions based on a simple user pattern like %%.%%%-%%-%%.%. But I wonder if there is any "built in" way to achieve this with php? I was thinking about sprintf etc., but that doesn't seem to do the trick. Any ideas?
I was thinking about sprintf etc., but that doesn't seem to do the trick.
You're on the right track. You can accomplish this with vsprintf as follows:
$str = '123ABC5678';
$pattern = '%%.%%%-%%-%%.%';
echo vsprintf(str_replace('%', '%s', $pattern), str_split($str));
Output:
12.3AB-C5-67.8
This is assuming the number of % characters in $pattern match the length of $str.
Why not write a simple parser that works as follows:
For each character of pattern:
if you match percent character, output next character from input
if you match any other character, output it
$str = '123ABC5678';
$pattern = '%%.%%%-%%-%%.%';
if (strlen($str) < substr_count($pattern, '%'))
Die('The length of input string is lower than number number of placeholders');
$len = strlen($pattern);
$stringIndex = 0;
$output = '';
for ($i = 0; $i < $len; $i++) {
if ($pattern[$i] === '%') {
$output .= $str[$stringIndex];
$stringIndex++;
} else {
$output .= $pattern[$i];
}
}
echo $output;
I have a similar solution that looks like this.
<?php
$format = '%%.%%%-%%-%%.%';
$string = '123ABC5678';
$new_string = '';
$c = 0;
for( $i = 0; $i < strlen( $format ); $i++ )
{
if( $format[ $i ] == '%' )
{
$new_string .= $string[ $c ];
$c++;
}
else
{
$new_string .= $format[ $i ];
}
}
echo $new_string;
Output:
12.3AB-C5-67.8
How about this pattern from the user?
2.3-2-2.1
Where the pattern is a number means n chars, a dot or dash means add a dot or dash.
Now you make a regex to parse the user input:
preg_match_all("/(.)/", $User_input, $pattern);
Now you will have an array with either numbers or dots and dashes.
So loop through the array and build the string:
$string = '123ABC5678';
$User_input = "2.3-2-2.1";
preg_match_all("/(.)/", $User_input, $pattern);
$i=0;
$str="";
foreach($pattern[1] as $val){
if(is_numeric($val)){
$str .= substr($string,$i,$val);
$i=$i+$val;
}else{
$str .= $val;
}
}
echo $str;
https://3v4l.org/5eg5G
I have E-20-99 in a string i want to get last value 99 and add 1 means 100 and then wants to generate new string E-20-100.
If your string ALWAYS looks like this, you can easily break it without a regex, simply by using explode()
$string = "E-20-99";
$parts = explode('-', $string);
$last_part = $parts[2] + 1;
$parts[2] = $last_part;
$string = implode('-', $parts);
echo $string;
If the string is always E-20-XX you can use
$n = ((int)substr('E-20-99', strlen('E-20-')))+1;
echo 'E-20-' . $n;
If the string might vary a bit more you could use a regualar expressions such as:
$string = 'E-20-99';
preg_match('/(E-\d+-)(\d+)/', $string, $match);
echo $match[1] . ((int)$match[2] + 1);
$old_str = 'E-20-99';
$new_str = preg_replace_callback('/(?<=-)\d+$/', function($matches) {
return $matches[0] + 1;
}, $old_str);
I'm trying strip every third character (in the example a period) below is my best guess and is close as ive gotten but im missing something, probably minor. Also would this method (if i could get it working) be better than a regex match, remove?
$arr = 'Ha.pp.yB.ir.th.da.y';
$strip = '';
for ($i = 1; $i < strlen($arr); $i += 2) {
$arr[$i] = $strip;
}
One way you can do it is:
<?php
$oldString = 'Ha.pp.yB.ir.th.da.y';
$newString = "";
for ($i = 0; $i < strlen($oldString ); $i++) // loop the length of the string
{
if (($i+1) % 3 != 0) // skip every third letter
{
$newString .= $oldString[$i]; // build up the new string
}
}
// $newString is HappyBirthday
echo $newString;
?>
Alternatively the explode() function might work, if the letter you're trying to remove is always the same one.
This might work:
echo preg_replace('/(..)./', '$1', 'Ha.pp.yB.ir.th.da.y');
To make it general purpose:
echo preg_replace('/(.{2})./', '$1', $str);
where 2 in this context means you are keeping two characters, then discarding the next.
A way of doing it:
$old = 'Ha.pp.yB.ir.th.da.y';
$arr = str_split($old); #break string into an array
#iterate over the array, but only do it over the characters which are a
#multiple of three (remember that arrays start with 0)
for ($i = 2; $i < count($arr); $i+=2) {
#remove current array item
array_splice($arr, $i, 1);
}
$new = implode($arr); #join it back
Or, with a regular expression:
$old = 'Ha.pp.yB.ir.th.da.y';
$new = preg_replace('/(..)\./', '$1', $old);
#selects any two characters followed by a dot character
#alternatively, if you know that the two characters are letters,
#change the regular expression to:
/(\w{2})\./
I'd just use array_map and a callback function. It'd look roughly like this:
function remove_third_char( $text ) {
return substr( $text, 0, 2 );
}
$text = 'Ha.pp.yB.ir.th.da.y';
$new_text = str_split( $text, 3 );
$new_text = array_map( "remove_third_char", $new_text );
// do whatever you want with new array