How to get SQL data to PHP array - php

Question

I kinda messed up the title, but i will try to explain my problem. i have a html page called leden.html and have a PHP script on it which gets data from my database and creates a table on the html page. Now the part where i get stuck is showing if a member is online and if someone is online the $sql1= "ja" else $sql1= "nee", but i messed up somewhere because when two people are online, the last person who came online shows online and the first dude goes back to "nee". Here is the code, i think something goes wrong at the array part.
<?php
$conn = mysqli_connect("******", "******", "******", "******");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, username, email FROM register";
$sessie_username = "SELECT username FROM sessie";
$result = $conn->query($sql);
$result1 = $conn->query($sessie_username);
$row1 = $result1->fetch_assoc();
$nameninsessie = array($row1["username"]);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if (in_array($row["username"], $nameninsessie)) {
$sql1 = "Ja";
} else {
$sql1 = "Nee";
}
echo "<tr><td>" . $row["id"]. "</td><td>" . $row["username"] . "</td>
<td>". $row["email"]. "</td><td>" . $sql1 . "</td></tr>";
}
echo "</table>";
} else { echo "0 resultaten"; }
$conn->close();
?>

Answer 1

You are only getting ONE of the logged in users from the sessie_username query. And also building the array of logged in users incorrectly. See below
<?php
$conn = mysqli_connect("******", "******", "******", "******");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, username, email FROM register";
$sessie_username = "SELECT username FROM sessie";
$result = $conn->query($sql);
$result1 = $conn->query($sessie_username);
// initialise the array
$nameninsessie = array();
// loop over all logged in users
while ( $row1 = $result1->fetch_assoc() ) {
// add thir names to an array
$nameninsessie[] = $row1["username"];
}
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if (in_array($row["username"], $nameninsessie)) {
$sql1 = "Ja";
} else {
$sql1 = "Nee";
}
echo "<tr><td>" . $row["id"]. "</td><td>" . $row["username"] . "</td>
<td>". $row["email"]. "</td><td>" . $sql1 . "</td></tr>";
}
echo "</table>";
} else { echo "0 resultaten"; }
$conn->close();
?>

Answer 2

There is a problem in your data fetching. See the returning array using print_rcommand. You only get the first value of the sql query. So try this. Furthermore you have to initialize the array if not when there is 0 results for the mysql query it will give an error.
<?php
$conn = mysqli_connect("localhost", "root", "*****", "*****");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, username, email FROM register";
$sessie_username = "SELECT username FROM sessie";
$result = $conn->query($sql);
$result1 = $conn->query($sessie_username);
$nameninsessie = array();
$i=0;
while($row1 = $result1->fetch_assoc()) {
$nameninsessie[$i] = $row1["username"];
$i++;
}
print_r($nameninsessie); //thi is to chek the array when problem solved please comment this line
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if (in_array($row["username"], $nameninsessie)) {
$sql1 = "Ja";
} else {
$sql1 = "Nee";
}
echo "<tr><td>" . $row["id"]. "</td><td> " . $row["username"] . "</td>
<td>". $row["email"]. "</td><td> " . $sql1 . "<br></td></tr>";
}
echo "</table>";
} else { echo "0 resultaten"; }
$conn->close();
?>