Sort array of days from a specific start date - php

Question

I have this array of days in a random order :
$jour_planning[] = "friday";
$jour_planning[] = "wednesday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
$jour_planning[] = "thursday";
$jour_planning[] = "sunday";
$jour_planning[] = "saturday";
If we are today a "tuesday", I would like to have this new array :
$jour_planning[] = "wednesday";
$jour_planning[] = "thursday";
$jour_planning[] = "friday";
$jour_planning[] = "saturday";
$jour_planning[] = "sunday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
How can do that, with usort() ?
Regards,
Vianney

Answer 1

I would first sort the array (and avoid french and english naming :) ).
Then, loop that sorted array and store into 2 separates array the days before the expected one (including this one), and the days after.
And finally, merge both arrays.
There's certainly better ways to do that.
$jour_planning[] = "friday";
$jour_planning[] = "wednesday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
$jour_planning[] = "thursday";
$jour_planning[] = "sunday";
$jour_planning[] = "saturday";
$sorted_days_planning = array(1 => null, 2 => null, 3 => null, 4 => null, 5 => null, 6 => null, 7 => null);
foreach ($jour_planning as $value)
{
$day_of_week = date('N', strtotime($value));
$sorted_days_planning[$day_of_week] = $value;
}
$final_days_planning = array();
$day_to_start = "tuesday";
$day_found = false;
$temp_array = array();
foreach ($sorted_days_planning as $value)
{
if (!$day_found)
{
$temp_array[] = $value;
if ($day_to_start == $value)
$day_found = true;
}
else
$final_days_planning[] = $value;
}
$final_days_planning = array_merge($final_days_planning, $temp_array);
var_dump($final_days_planning);
Outputs :
array(6) {
[0]=> string(9) "wednesday"
[1]=> string(8) "thursday"
[2]=> string(6) "friday"
[3]=> string(8) "saturday"
[4]=> string(6) "sunday"
[5]=> string(6) "monday"
[6]=> string(7) "tuesday"
}

Answer 2

You can rearrange your array using uksort(), date() and strtotime().
function sort_week_days( $t1, $t2 ) {
$weekdays = array( 'sunday', 'monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday' );
foreach ( $weekdays as $key => $value ) {
$weekdays[ $key ] = date( 'w', strtotime( $value ) );
}
$t1_time = date( 'w', strtotime( strtolower( $t1 ) ) );
$t2_time = date( 'w', strtotime( strtolower( $t2 ) ) );
return array_search( $t1_time, $weekdays ) - array_search( $t2_time, $weekdays );
}
You need to pass your random array as below :
usort($jour_planning, "sort_week_days");
Then you can used your array in below code :
$day = date('w'); // You need to change to date('w', '-1day'); get result from today.
for ($i=0; $i <= $day ; $i++) {
array_push($jour_planning, array_shift($jour_planning));
}

Answer 3

Because of your array is randomly ordered, there is no other way to order it correctly, then doing it by hand (you cannot order the array numerically or alphabetically - it can be done by calculating the days by the datetime() function, see #Cid's answer), so:
/*
$jour_planning = [];
$jour_planning[] = "friday";
$jour_planning[] = "wednesday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
$jour_planning[] = "thursday";
$jour_planning[] = "sunday";
$jour_planning[] = "saturday";
*/
$days = [
0 => 'monday',
1 => 'tuesday',
2 => 'wednesday',
3 => 'thursday',
4 => 'friday',
5 => 'saturday',
6 => 'sunday'
];
$today = array_search(strtolower(date('l')), $days);
$tomorrow = ($today === 6) ? 0 : $today + 1;
$reordered = array_merge(array_slice($days, $tomorrow), array_slice($days, 0, $tomorrow));
print_r($reordered);
Firstly you have to search the current day, then add 1 to the index of this day and you have the day, that will be tomorrow. Now, when you have this index, you simply create 2 arrays: the first one starting from the day of tomorrow and the second one starting from index 0 to the day of today. Then merge this two arrays together and you have exactly what you wanted to have.

Answer 4

You can use this function to sort week days and it's has option to include the first day.
function sort_days($day_to_start = 'monday', $include_first_day = true)
{
$final_days_planning = [];
$rest_days = [];
$first_day_found = 0;
foreach ([ "sunday", "monday", "tuesday", "wednesday", "thursday", "friday", "saturday" ] as $day)
{
if (!$first_day_found){
if ($day_to_start == $day){
$first_day_found = 1;
if($include_first_day){
$final_days_planning[] = $day;
}
else
{
$rest_days[] = $day;
}
}
else
{
$rest_days[] = $day;
}
} else{
$final_days_planning[] = $day;
}
}
return array_merge($final_days_planning, $rest_days);
}
To try it:
$days = sort_days('wednesday');
print_r($days);

Answer 5

You can use in_array to find the days present in your array and add to new array.
$jour_planning=["saturday","wednesday","friday","thursday"];
public function getSortedDays($jour_planning){
$sorted_days=[];
for($i=1;$i<=7;$i++){
$day = date("l", strtotime("+$i days"));
$_day = strtolower($day);
if(in_array($_day, $jour_planning)){
$sorted_days[] = $_day;
}
}
return $sorted_days;
}
$sorted_days = getSortedDays($jour_planning);
print_r($sorted_days); //Array ( [0] => wednesday [1] => thursday [2] => friday [3] => saturday )

Answer 6

while (end($jour_planning) !== "tuesday") {
array_unshift($jour_planning, array_pop($jour_planning));
}