Update database with two array parameters - php

Question

I´m trying to update my database with information that is send via a form.
My problem is that i don´t get how I can loop both arrays at the same. I have tried nesting foreach-loops with no success.
I then have this to work with
$display = $_POST["show"] ?? "";
$id = array_keys($_POST["show"]);
if ($action == "submit") {
foreach ($display as $key => $value) {
$stmt = $db->prepare("UPDATE picture SET display = ? WHERE id = ?");
$stmt->bindParam($display, $id)
$stmt->execute();
}
}

Answer 1

You can iterate over array and get keys and values at the same time:
$display = $_POST["show"] ?? [];
// Also you can check if `$display` is not empty
if ($action == "submit" && $display) {
// prepare statement ONCE
$stmt = $db->prepare("UPDATE picture SET display = ? WHERE id = ?");
foreach ($display as $key => $value) {
// execute statement as many times as you want with your params
$stmt->execute([$value, $key]);
}
}

Answer 2

If I saw correctly this is what you want:
<?php
try {
$display = isset($_POST['show']) ? $_POST['show'] : [];
if ($action === 'submit' && !empty($display)) {
$db->beginTransaction();
$stmt = $db->prepare('
UPDATE picture
SET display = :display
WHERE id = :id;
');
foreach ($display as $id => $show) {
$stmt->bindParam(':display', $show);
$stmt->bindParam(':id', $id, PDO::PARAM_INT);
$stmt->execute();
}
$db->commit();
}
} catch(PDOException $e) {
echo $e->getMessage();
$db->rollBack();
}