Php find and replace words in a text from database tables - php

Question

I'm working on a project. It searches and replaces words from the database in a given text. In the database a have 10k words and replacements. So ı want to search for each word and replace this word's replacement word.
By the way, I'm using laravel. I need only replacement ideas.
I have tried some ways but it replaces only one word.
My database table structure like below;
id word replacement
1 test testing
etc
The text is coming from the input and after the replacement, I wanna show which words are replaced in a different bg color in the result page.
I tried below codes working fine but it only replaces one word.
$article = trim(strip_tags($request->article));
$clean = preg_split('/[\s]+/', $article);
$word_count = count($clean);
$words_from_database_for_search = Words::all();
foreach($words_from_database_for_search as $word){
$content = str_replace($word['word'],
"<span class=\"badge badge-success\">$word[replacement]
</span>",
$article);
}
$new_content = $content ;
$new_content_clean = preg_split('/[\s]+/', $new_content);
$new_content_word_count= count($new_content_clean);
Edit,
Im using preg_replace instead of str_replace. I get it worked but this time i wanna show how many words changed so i tried to find the number of changed words from the text after replacement. It counts wrong.
Example if there is 6 changes it show 3 or 4
It can be done via preg_replace_callback but i didnt use it before so i dont know how to figure out;
My working codes are below;
$old_article = trim(strip_tags($request->article));
$old_article_word_count = count($old_article );
$words_from_database_array= Words::all();
$article_will_replace = trim(strip_tags($request->article));
$count_the_replaced_words = 0;
foreach($words_from_database_array as $word){
$article_will_replace = preg_replace('/[^a-zA-
ZğüşıöçĞÜŞİÖÇ]\b'.$word['word'].'\b\s/u',
" <b>".$word['spin']."</b> ",
$article_will_replace );
$count_the_replaced_words = preg_match_all('/[^a-zA-
ZğüşıöçĞÜŞİÖÇ]\b'.strip_tags($word['spin']).'\b\s/u',$article_will_replace
);
if($count_the_replaced_words ){
$count_the_replaced_words ++;
}
}

Answer 1

As others have suggested in comments, it seems your value of $content is being overwritten on each run of the foreach loop, with older iterations being ignored. That's because the third argument of your str_replace is $article, the original, unmodified text. Only the last word, therefore, is showing up on the result.
The simplest way to fix this would be to declare $content before the foreach loop, and then make $content the third argument of the foreach loop so that it is continually replaced with a new word on each iteration, like so:
$content = $article;
foreach($words_from_database_for_search as $word){
$content = str_replace($word['word'],
"<span class=\"badge badge-success\">$word[replacement]</span>",
$content);
}

Answer 2

Im confused, don't you need the <?php ... ?> around the $word[replacement] ?
foreach($words_from_database_for_search as $word){
$content = str_replace($word['word'],
"<span class=\"badge badge-success\"><?PHP $word[replacement] ?>
</span>",
$article);
}
and then move this in to the for-loop and add a dot before the equal-sign:
$new_content .= $content ;