Show different data in webpage when clicked depending on the ID - php

Question

I am trying to show user data when clicking link depending on a story ID. However, the page is showing the same data from one row in the database every time (web link is showing a different ID 'php?story_id=10' etc. but it's still showing the same data.
I have this function:
function displayStories(){
include('conn/conn.php');
$queryread = "SELECT Users.ID, Users.FirstName, Stories.Age, Stories.Story,
Stories.Image FROM `Stories` INNER JOIN `Users` ON Users.ID = Stories.User_ID";
$result = mysqli_query($conn, $queryread) or die(mysqli_error($conn));
if(mysqli_num_rows($result) > 0 ){
while($row = mysqli_fetch_assoc($result)){
$name = $row["FirstName"];
$idData = $row["ID"];
$age = $row["Age"];
$story = $row["Story"];
$limit = mb_strimwidth($story, 0, 300, "...");
echo
"<div class='stories'>
<a href='storyDis.php?story_id=$idData'>
<h5><b>$name</b></h5></a>
<p><b>$age years old</b></p>
<p>$limit</p>
</div>
";
}
}
mysqli_close($conn);
}
And this to query to display the data(variables called in HTML):
include('conn/conn.php');
$str = htmlentities($_GET["story_id"]);
$query = "SELECT * "
. "FROM Stories "
. "WHERE ID='$str'";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn));
$queryread = "SELECT Users.FirstName, Stories.Age, Stories.Story,
Stories.Image FROM `Stories` INNER JOIN `Users` ON Users.ID = Stories.User_ID";
$result1 = mysqli_query($conn, $queryread) or die(mysqli_error($conn));
if(mysqli_num_rows($result1) > 0 ){
while($row = mysqli_fetch_assoc($result1)){
$name = $row["FirstName"];
$age = $row["Age"];
$story = $row["Story"];
$image = $row["Image"];
}
}
mysqli_close($conn);
?>
EDIT
Had two queries when I only needed one.
$str = htmlentities($_GET["story_id"]);
$queryread = "SELECT Stories.ID, Users.FirstName, Stories.Age, Stories.Story, Stories.Image FROM `Stories` INNER JOIN `Users` ON Users.ID = Stories.User_ID
WHERE Stories.ID='$str'";
$result1 = mysqli_query($conn, $queryread) or die(mysqli_error($conn));
if(mysqli_num_rows($result1) > 0 ){
while($row = mysqli_fetch_assoc($result1)){
$name = $row["FirstName"];
$age = $row["Age"];
$story = $row["Story"];
$image = $row["Image"];
}
}
mysqli_close($conn);
?>

Answer 1

you are reading the data from (result1) not from (result).
Change this one while($row = mysqli_fetch_assoc($result1)){
to
while($row = mysqli_fetch_assoc($result)){
and then it will works fine with you .