How to output php search result to html table? - php

Question

Want to output search result from database into an html table, but all I'm getting is a printed array. Fairly certain that's due to "print_r", but how do I output to html table instead and getting shown more than just the first result?
My html table using data from my database works fine - but there I'm just using a "SELECT *" with no user input.
I've tried playing around with my php-code that works with just the "SELECT *", but no luck.
<?php
$servername = "test";
$username = "test";
$password = "test";
$dbname = "test";
$journal = (isset($_SESSION["journal"])) ? $_SESSION["journal"]
: null;
$conn = mysqli_connect($servername, $username, $password, $dbname) or die("connection failed: " . mysqli_connect_error());
mysqli_select_db($conn, $dbname) or die("something went wrong");
if(isset($_POST["form_submit"]))
{
$journal =$_POST["journal"];
$stmt = $conn->prepare("SELECT * FROM straffesager WHERE journalnummer=?");
$stmt->bind_param("s",$journal);
$stmt->execute();
$val = $stmt->get_result();
$row_count= $val->num_rows;
if($row_count >0)
{
$result =$val->fetch_assoc();
print_r($result);
}
else{
echo "<br><br>Den indtastede information matcher ikke sager i databasen.";
}
$stmt->close();
$conn->close();
}
?>
This is my result: "Array ( [idnumber] => 4 [journalnummer] => 17-1717171 [status] => lukket".
The result above is just text. I'd like it to be in the html table I'm using somewhere else as well.
How do I output the result from my code to an HTML table and have more than one search result being shown?
Thanks for helping out a rookie.

Answer 1

instead of
$result =$val->fetch_assoc();
print_r($result);
you should print your table with help of your $result variable
like this
echo "<table><tr><th>HEAD1</th><th>HEAD2</th><th>HEAD3</th></tr>";
while ($row = $val->fetch_assoc()) {
printf("<tr><td>%s</td><td>%s</td><td>%s</td></tr>",
$row['idnumber'],$row['journalnummer'],$row['status']);
//it will put $row instead of %s
}
echo "</table>";