PHP array_sum outputs individual numbers rather than as a whole - php

Question

I have this list of "coupons" each with a unique "productid"
Now I am trying to convert the list into an array using:
$claimed = array($rowOrder['productid']);
My issue is when I try to use "count" and "array_sum" it outputs individual numbers:
$count_claimed = array(count($claimed));
echo array_sum($count_claimed);
Using the echo I get and output of: "1111111"
What should I change to get a sum count of 7? (as displayed with the number of "coupons")
additional info:
The "coupons" are being outputted by this SELECT statement, $rowOrder is calling this.
public function SelectLst_ByUsrCustomerIDInfo($db, $usrcustomerid) {
$stmt = $db->prepare(
" SELECT o.orderid, o.productid, o.usrcustomerid, o.amount, o.amountrefunded, o.createddate, o.scheduleddate, o.useddate, o.expirationdate, p.photosrc
FROM `order` o LEFT JOIN `product` p ON o.productid = p.productid
WHERE usrcustomerid = :usrcustomerid"
);
$stmt->bindValue(':usrcustomerid', $usrcustomerid, PDO::PARAM_INT);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
return $rows;
}
This is called like this
$lstInfo = $mcOrder->SelectLst_ByUsrCustomerIDInfo($db, $usrcustomerid);
foreach($lstInfo as $rowOrder) {
if (isset($rowOrder['productid']) && ($rowOrder['expirationdate'] > date("Y-m-d H:i:s"))) {
$claimed = array($rowOrder['productid']);
$count_claimed = array(count($claimed));
echo array_sum($count_claimed);
}
}

Answer 1

Doing count($lstInfo) you will get the total number of fetched rows (PDOStatement::fetchAll() returns an array, and you just count the number of elements in it). Then you can loop the results and increment a variable called $claimed if the condition is true.
$lstInfo = $mcOrder->SelectLst_ByUsrCustomerIDInfo($db, $usrcustomerid);
$total = count($lstInfo);
$claimed = 0;
foreach($lstInfo as $rowOrder) {
if (isset($rowOrder['productid']) && ($rowOrder['expirationdate'] > date("Y-m-d H:i:s"))) {
$claimed += 1;
}
}
echo "Claimed $claimed of $total.";
Even better, you can do it in one query using a COUNT() and an added WHERE condition. This means you won't get the total, but that didn't seem to be the question to begin with either.
$stmt = $db->prepare("SELECT COUNT(productid) as cnt
FROM `order` o
LEFT JOIN `product` p
ON o.productid = p.productid
WHERE usrcustomerid = :usrcustomerid
AND expirationdate > NOW()
GROUP BY usrcustomerid");
$stmt->execute([":usrcustomerid" => $usrcustomerid]);
$result = $stmt->fetch();
echo "Claimed ".$result['cnt'];

Answer 2

Try This,
$claimed = array();
foreach($products as $rowOrder){
array_push($claimed,$rowOrder['productid']);
}
echo count($claimed);
echo array_sum($claimed);die;