Multiple Result Data in json Response - php

Question

I am new in PHP and trying to build one API which provide me json response of required data. There one table called user and I need email, username and user_type from it. I have coded like below for do it
$result = array();
$users = getOnlineUsers($conn);
$userinfo['email'] = $users['email'];
$userinfo['username'] = $users['username'];
$userinfo['user_type'] = $users['user_type'];
$result['status'] ="success";
$result['userData'] = $userinfo;
And function is like below
function getOnlineUsers($conn)
{
$q = $conn->prepare("SELECT * FROM table_users WHERE online_status = 1");
// $q->bind_param("s", $email);
$q->execute();
$result = $q->store_result();
$metaResults = $q->result_metadata();
$fields = $metaResults->fetch_fields();
$statementParams='';
foreach($fields as $field){
if(empty($statementParams)){
$statementParams.="\$column['".$field->name."']";
}else{
$statementParams.=", \$column['".$field->name."']";
}
}
$statment="\$q->bind_result($statementParams);";
eval($statment);
$q->fetch();
return $column;
}
Its working fine but giving me only one row in response. I want get all row instead of one. I am getting response like this
{"status":"success","userData":{"email":"abc#gmail.com","username":"rajrathodbvn","user_type":0}}
Let me know if someone can help me for solve my issue.
Thanks

Answer 1

That's a lot of code for something so simple. Select the columns you want:
function getOnlineUsers($conn) {
$q = $conn->prepare("SELECT email, username, user_type
FROM table_users
WHERE online_status = 1");
$q->execute();
return $q->fetchAll(PDO::FETCH_ASSOC);
}
Then assign:
$result['status'] = 'success';
$result['userData'] = getOnlineUsers($conn);
Or:
$result = ['status' => 'success', 'userData' => getOnlineUsers($conn)];