I can't get the content of a specific URL - php

Question

I can't get the content of this URL (I get a blank page): https://www.euronews.com/api/watchlive.json
I have always used this function and never had problems:
function file_get_contents_curl($url)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 3);
curl_setopt($ch, CURLOPT_TIMEOUT, 3);
curl_setopt($ch, CURLOPT_REFERER, $referer);
curl_setopt($ch, CURLOPT_AUTOREFERER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $header);
curl_setopt($ch, CURLOPT_HEADER, 5);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_USERAGENT, $useragent);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie);
curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
$data = json_decode(file_get_contents_curl("https://www.euronews.com/api/watchlive.json"), true); $url = $data['url']; echo $url;
Any idea?
EDIT: Unknown problem caused (possibly) by cURL module in Raspbian (Raspberry)

Answer 1

I think you need to echo the function if you want to see the content. I tried this on my end and I got the content. althought I have some undefined variable error because of $referrer, $header, $useragent and $cookie. but it runs and get the result. here is how I call the function
echo file_get_contents_curl("https://www.euronews.com/api/watchlive.json");

Answer 2

You're getting more than you expect in your function response, so the json_decode is failing. You need to set CURLOPT_HEADER to false instead of 5.
curl_setopt($ch, CURLOPT_HEADER, FALSE);
You can verify what you're getting by doing
$response = file_get_contents_curl("https://www.euronews.com/api/watchlive.json");
var_dump($response);
$data = json_decode($response, true);
$url = $data['url'];
echo $url;