How do I get a value outside the loop using PHP [duplicate] - php

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Closed 3 years ago.
I'm creating a small website using PHP, which is generally a site for showcasing the hospital, and I modified the code given in this example:
https://www.w3schools.com/php/php_mysql_select.asp
<?php
$query = "SELECT * FROM emp WHERE type = 'woman' ";
$result = mysqli_query($db, $query);
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$cat = $row["cat"] . ',';
echo $cat;
////<---- echo on while (Loop)
}
}
The expected output would be as follows:
Output: 35,36
But I changed the code with the link above and it is as follows:
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$cat = $row["cat"] . ',';
}
echo $cat;
///// <---- echo Out of While (Loop)
}
Output: 35
My expecting output would be 35, 36 outside of "while" using "echo".
What code do you recommend to output "35,36" the same code above?

Answer 1

You can try the below code to achive your requirement
$data = array();
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result)) {
$data[] = $row["cat"];
}
}
echo implode(",",$data);