Foreach loop only showing last item in array in api - php

Question

I am making a CRUD API for my android app, all this API needs to do is check the database for information regarding an indeterminate incoming user ID's and return the query results to the app(the R in CRUD). I have gotten the API to query and output both single item arrays and the last Item in the array.
my code:
$jsonobj = '{"code":"ascaasease","code":"ascaesease","code":"onetoelevn"}';
//mock json
$obj = json_decode($jsonobj);
foreach($obj as $key => $value) {
$sql = "SELECT code, header, body FROM `messages` WHERE code= '$value'";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
$response['code'] = $row["code"];
$response['header'] = $row["header"];
$response['body'] = $row["body"];
$array_push[] = $response;
}
}
mysqli_close($conn);
}
$return = array("resoponse"=>array("check"=>"check"),"array"=>$array_push);
echo json_encode($return);
in this configuration, it will just output the final item in the array ("code","onetoelevn"). If the formating is dropped, and you tell the script to just echo the response it still only displays the last item in the array.
if you could tell me how to run an SQL query on each item in the array I would be very thankful.

Answer 1

First of all, your mock JSON is broken. It contains repeated properties.
If you must use a loop (which you don't have to) you can prepare the statement before the loop and execute within. Then use get_result() and fetch_all() to get the data.
mysqli
//mysqli connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli('localhost', 'user', 'password', 'db_name');
$conn->set_charset('utf8mb4'); // always set the charset
$jsonobj = '[ "ascaasease", "onetoelevn"]';
//mock json
$obj = json_decode($jsonobj);
$stmt = $conn->prepare('SELECT code, header, body FROM messages WHERE code=?');
$stmt->bind_param('s', $value);
$array_push = [];
foreach ($obj as $key => $value) {
$stmt->execute();
$data = $stmt->get_result()->fetch_all(MYSQLI_ASSOC);
$array_push = array_merge($array_push, $data);
}
$return = array("resoponse" => array("check" => "check"), "array" => $array_push);
echo json_encode($return);
If you don't have to use a loop, then you can use WHERE IN()
$jsonobj = '[ "ascaasease", "onetoelevn"]';
//mock json
$obj = json_decode($jsonobj);
$wherein = str_repeat(',?', count($obj) - 1);
$stmt = $conn->prepare("SELECT code, header, body FROM messages WHERE code IN(? $wherein )");
$stmt->bind_param(str_repeat('s', count($obj)), ...$obj);
$stmt->execute();
$array_push = $stmt->get_result()->fetch_all(MYSQLI_ASSOC);
$return = array("resoponse" => array("check" => "check"), "array" => $array_push);
echo json_encode($return);
PDO
Of course, all of this would be simpler if you were using PDO. If it is not too late, can you consider switching over to PDO instead of using mysqli?
Option 1:
// PDO connection
$pdo = new PDO("mysql:host=localhost;dbname=db_name;charset=utf8mb4", 'user', 'password', [
\PDO::ATTR_ERRMODE => \PDO::ERRMODE_EXCEPTION,
\PDO::ATTR_EMULATE_PREPARES => false
]);
$jsonobj = '[ "ascaasease", "onetoelevn"]';
//mock json
$obj = json_decode($jsonobj);
$stmt = $pdo->prepare('SELECT code, header, body FROM messages WHERE code=?');
$array_push = [];
foreach ($obj as $key => $value) {
$stmt->execute([$value]);
$data = $stmt->fetchAll(PDO::FETCH_ASSOC);
$array_push = array_merge($array_push, $data);
}
$return = array("resoponse" => array("check" => "check"), "array" => $array_push);
echo json_encode($return);
Option 2:
$jsonobj = '[ "ascaasease", "onetoelevn"]';
//mock json
$obj = json_decode($jsonobj);
$wherein = str_repeat(',?', count($obj) - 1);
$stmt = $pdo->prepare("SELECT code, header, body FROM messages WHERE code IN(? $wherein )");
$stmt->execute($obj);
$array_push = $stmt->fetchAll(PDO::FETCH_ASSOC);
$return = array("resoponse" => array("check" => "check"), "array" => $array_push);
echo json_encode($return);