I have a column in a table that I would like to add up and return the sum. I have a loop, but it's not working.
while ($row = mysql_fetch_assoc($result)){
$sum += $row['Value'];
}
echo $sum;
You can completely handle it in the MySQL query:
SELECT SUM(column_name) FROM table_name;
Using PDO (mysql_query is deprecated)
$stmt = $handler->prepare('SELECT SUM(value) AS value_sum FROM codes');
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$sum = $row['value_sum'];
Or using mysqli:
$result = mysqli_query($conn, 'SELECT SUM(value) AS value_sum FROM codes');
$row = mysqli_fetch_assoc($result);
$sum = $row['value_sum'];
$query = "SELECT * FROM tableName";
$query_run = mysql_query($query);
$qty= 0;
while ($num = mysql_fetch_assoc ($query_run)) {
$qty += $num['ColumnName'];
}
echo $qty;
Try this:
$sql = mysql_query("SELECT SUM(Value) as total FROM Codes");
$row = mysql_fetch_array($sql);
$sum = $row['total'];
Let us use the following image as an example for the data in our MySQL Database:
Now, as the question mentions, we need to find the sum of a particular column in a table. For example, let us add all the values of column "duration_sec" for the date '09-10-2018' and only status 'off'
For this condition, the following would be the sql query and code:
$sql_qry = "SELECT SUM(duration_sec) AS count
FROM tbl_npt
WHERE date='09-10-2018' AND status='off'";
$duration = $connection->query($sql_qry);
$record = $duration->fetch_array();
$total = $record['count'];
echo $total;
MySQL 5.6 (LAMP) . column_value is the column you want to add up. table_name is the table.
Method #1
$qry = "SELECT column_value AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
while ($rec = $db->fetchAssoc($res)) {
$total += $rec['count'];
}
echo "Total: " . $total . "\n";
Method #2
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
$rec = $db->fetchAssoc($res);
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #3 -SQLi
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $conn->query($sql);
$total = 0;
$rec = row = $res->fetch_assoc();
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #4: Depreciated (don't use)
$res = mysql_query('SELECT SUM(column_value) AS count FROM table_name');
$row = mysql_fetch_assoc($res);
$sum = $row['count'];
$row['Value'] is probably a string. Try using intval($row['Value']).
Also, make sure you set $sum = 0 before the loop.
Or, better yet, add SUM(Value) AS Val_Sum to your SQL query.
$result=mysql_query("SELECT SUM(column) AS total_value FROM table name WHERE column='value'");
$result=mysql_result($result,0,0);
Get Sum Of particular row value using PHP MYSQL
"SELECT SUM(filed_name) from table_name"
$sql = "SELECT SUM(Value) FROM Codes";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
sum = $row['SUM(price)'];
}
echo sum;
Related
for ($i=$start; $i<$start+$scale && $i < $total_record; $i++)
{
$sql = "select * from memo where num = ?";
$stmh = $pdo->prepare($sql);
//mysql_data_seek($result, $i);
$row = mysql_fetch_array($result);
$sql2 = "select * from phptest.memo order by num desc";
$stmh2 = $pdo->query($sql2);
$stmh2->execute();
//$row = $stmh2->fetch(PDO::FETCH_ASSOC);
$row = $stmh->fetchColumn($i-1);
$memo_id = $row['id'];
$memo_num = $row['num'];
$memo_date = $row['regist_day'];
$memo_nick = $row['nick'];
$memo_content = $row['content'];
Hi guys i want fetch single row data by using PDO method instead of $row = $stmh2->fetch(PDO::FETCH_ASSOC); like mysqli_data_seek($result,$i);. What should i do?
$sql2 = "select * from phptest.memo order by num desc";
$stmh2 = $pdo->query($sql2);
$stmh2->execute();
while($r = $stmh2->fetch()) {$row[] = $r;}
Now $row[$i] should be getting you the same results as mysqli_data_seek($result,$i) would have.
IE: $row[0] would return the first row.
Following is my code,
$result1 = "SELECT emp_id FROM employee where manager_id=".$userID;
$array = mysql_query($result1);
$cnt = 0;
while ($row = mysql_fetch_array($array)) {
"emp_id: " . $row[0];
$myArrayOfemp_id[$cnt] = $row[0];
$cnt++;
}
var_dump($myArrayOfemp_id);
$sql = "SELECT emp_id FROM emp_leaves WHERE emp_id='$myArrayOfemp_id' ORDER BY apply_date DESC";
$result = mysql_query($sql);
$total_results = mysql_num_rows($result);
When I'am trying to use $myArrayOfemp_id variable in $sql query, It shows that error:
Array to string conversion in..
How can I fix it?
You are trying to convert an array into a string in the following line:
$sql = "SELECT emp_id FROM emp_leaves
WHERE emp_id='$myArrayOfemp_id' ORDER BY apply_date DESC";
$myArrayOfemp_id is an array. That previous line of code should be changed to:
$sql = "SELECT emp_id FROM emp_leaves
WHERE emp_id={$myArrayOfemp_id[0]} ORDER BY apply_date DESC";
I placed 0 inside {$myArrayOfemp_id[0]} because I'm not sure what value want to use that is inside the array.
Edited:
After discussing what the user wanted in the question, it seems the user wanted to use all the values inside the array in the sql statement, so here is a solution for that specific case:
$sql = "SELECT emp_id FROM emp_leaves
WHERE ";
foreach ($myArrayOfemp_id as $value)
{
$sql .= " emp_id={$value) || ";
}
$sql .= "1=2";
$result = mysql_query($sql);
$total_results = mysql_num_rows($result);
$sql = "SELECT emp_id FROM emp_leaves WHERE emp_id in
(SELECT GROUP_CONCAT(emp_id) FROM employee where manager_id=".$userID.")
ORDER BY apply_date DESC";
$result = mysql_query($sql);
$total_results = mysql_num_rows($result);
just change your query like above might solve your problem.
you can remove following code now. :)
$result1 = "SELECT emp_id FROM employee where manager_id=".$userID;
$array = mysql_query($result1);
$cnt = 0;
while ($row = mysql_fetch_array($array)) {
"emp_id: " . $row[0];
$myArrayOfemp_id[$cnt] = $row[0];
$cnt++;
}
var_dump($myArrayOfemp_id);
I am trying to store a mysql value into a php variable. I have the following query which I know works. However, I the value for $count is always 0. Can someone explain what I need to do to get the count value? The count should be the count of x's w here name_x=.$id.
$query = "SELECT COUNT(name_x) FROM Status where name_x=.$id.";
$result = mysql_query($query);
$count = $result;
Is first letter in table name is really capital. Please check it first.
or Try :
$query = "SELECT COUNT(*) as totalno FROM Status where name_x=".$id;
$result = mysql_query($query);
while($data=mysql_fetch_array($result)){
$count = $data['totalno'];
}
echo $count;
$query = "SELECT COUNT(*) FROM `Status` where `name_x`= $id";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
$count = $row[0];
please try it
$query = "SELECT COUNT(*) FROM Status where name_x=$id";
$result = mysql_query($query);
$count = mysql_result($result, 0);
You are missing single quotes around $id. Should be
name_x = '" . $id . "'";
$query = $db->query("SELECT * FROM orders");
while ($row = mysql_fetch_array($query)) {
$cost= array_sum($row['cost']);
}
This is not working, I want to to calculate the sum of all elements but I get this error:
Warning: array_sum() expects parameter
1 to be array, string given in
C:\xampp\htdocs\falco\classes\controller.php
on line 303
Any idea how to calculate all the elements coming from mysql?
Thank you for your time and help.
Why not let MYSQL handle it?
$query = $db->query("SELECT orders.*,SUM(cost) as sum_cost FROM orders");
If its just a sum you want you can let the database do it for you:
Select sum(cost) from orders
Try this:
$query = $db->query("SELECT * FROM orders");
$cost = 0;
while ($row = mysql_fetch_array($query)) {
$cost += $row['cost'];
}
Or from mysql:
$query = $db->query("SELECT sum(`cost`) as `cost` FROM orders");
while ($row = mysql_fetch_array($query)) {
$cost = $row['cost'];
}
this should work:
$query = $db->query("SELECT * FROM orders");
$cost = 0;
while ($row = mysql_fetch_array($query)) {
$cost += $row['cost'];
}
or even better
$query = $db->query("SELECT SUM(cost) FROM orders");
list($cost) = mysql_fetch_row($query);
Really, it sounds like you just want the sum.
'SELECT SUM(cost) as sum_cost FROM ORDERS'
I have a column in a table that I would like to add up and return the sum. I have a loop, but it's not working.
while ($row = mysql_fetch_assoc($result)){
$sum += $row['Value'];
}
echo $sum;
You can completely handle it in the MySQL query:
SELECT SUM(column_name) FROM table_name;
Using PDO (mysql_query is deprecated)
$stmt = $handler->prepare('SELECT SUM(value) AS value_sum FROM codes');
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$sum = $row['value_sum'];
Or using mysqli:
$result = mysqli_query($conn, 'SELECT SUM(value) AS value_sum FROM codes');
$row = mysqli_fetch_assoc($result);
$sum = $row['value_sum'];
$query = "SELECT * FROM tableName";
$query_run = mysql_query($query);
$qty= 0;
while ($num = mysql_fetch_assoc ($query_run)) {
$qty += $num['ColumnName'];
}
echo $qty;
Try this:
$sql = mysql_query("SELECT SUM(Value) as total FROM Codes");
$row = mysql_fetch_array($sql);
$sum = $row['total'];
Let us use the following image as an example for the data in our MySQL Database:
Now, as the question mentions, we need to find the sum of a particular column in a table. For example, let us add all the values of column "duration_sec" for the date '09-10-2018' and only status 'off'
For this condition, the following would be the sql query and code:
$sql_qry = "SELECT SUM(duration_sec) AS count
FROM tbl_npt
WHERE date='09-10-2018' AND status='off'";
$duration = $connection->query($sql_qry);
$record = $duration->fetch_array();
$total = $record['count'];
echo $total;
MySQL 5.6 (LAMP) . column_value is the column you want to add up. table_name is the table.
Method #1
$qry = "SELECT column_value AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
while ($rec = $db->fetchAssoc($res)) {
$total += $rec['count'];
}
echo "Total: " . $total . "\n";
Method #2
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $db->query($qry);
$total = 0;
$rec = $db->fetchAssoc($res);
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #3 -SQLi
$qry = "SELECT SUM(column_value) AS count
FROM table_name ";
$res = $conn->query($sql);
$total = 0;
$rec = row = $res->fetch_assoc();
$total = $rec['count'];
echo "Total: " . $total . "\n";
Method #4: Depreciated (don't use)
$res = mysql_query('SELECT SUM(column_value) AS count FROM table_name');
$row = mysql_fetch_assoc($res);
$sum = $row['count'];
$row['Value'] is probably a string. Try using intval($row['Value']).
Also, make sure you set $sum = 0 before the loop.
Or, better yet, add SUM(Value) AS Val_Sum to your SQL query.
$result=mysql_query("SELECT SUM(column) AS total_value FROM table name WHERE column='value'");
$result=mysql_result($result,0,0);
Get Sum Of particular row value using PHP MYSQL
"SELECT SUM(filed_name) from table_name"
$sql = "SELECT SUM(Value) FROM Codes";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)){
sum = $row['SUM(price)'];
}
echo sum;