How can I create an array from the results of 2 queries? - php

Question

I'm trying to create an array from the results of 2 queries, and send it all together to front-end, but I'm stuck to the point where I need to push the results of the second query to the array, I tried to do it using array_push but doesn't work.
Let's say we have this example, and I need to include the results of $query2 to $return_arr
Any ideas?
<?php
header('Access-Control-Allow-Origin: *');
include "config.php";
$return_arr = array();
$query1 = "SELECT * FROM balance WHERE class='income' ORDER BY id DESC";
$query2 = "SELECT * FROM balance WHERE class='expense' ORDER BY id DESC";
$result1 = mysqli_query($conn,$query1);
while($row = mysqli_fetch_array($result1)){
$id = $row['id'];
$description = $row['description'];
$date = $row['date'];
$euro = $row['euro'];
$who = $row['who'];
$class = $row['class'];
$return_arr[] = array("id_income" => $id,
"description_income" => $description,
"date_income" => $date,
"euro_income" => $euro,
"who_income" => $who,
"class_income" => $class
);
}
// Encoding array in JSON format
echo json_encode($return_arr);

Answer 1

Here's a different query:
SELECT *
FROM balance
WHERE class IN('income','expense')
ORDER
BY class
, id DESC

Answer 2

Like JS Bach answer. But maybe you could speed up performance by mention the column's name.
SELECT column1, column2, column3 FROM balance WHERE class IN ('income','expense') ORDER BY class, id DESC;

Answer 3

You can also make use of OR operator
$query = SELECT * FROM balance WHERE class = "income" OR class = "expense" ORDER BY class, id DESC;
$result = mysqli_query($conn,$query);
$array = mysqli_fetch_array($result,MYSQLI_ASSOC);
Your fetched records will already be in an array format in $array
This can be more effective when dealing with tables having records in 1000s of rows