SQL How to order by differents times - php

Question

Hi, I have created in the db two rows for one flight, one for the arrival and another for departure. Now Ineed to order by arrival time and departure time in the order.
This is my code but it's not working.
In the date that I've selected I have to display the arrivals and departures in the rights order eg:
Flight 1 : arr 10:30
Flight 2 : dep 10:55
Flight 1 : Dep 11:00
Flight 5 : Dep 11:20
And so on....
$sqlArr = "SELECT * FROM flights WHERE arr_date = '$date' OR dep_date = '$date' ORDER BY
eta,etd ASC";
$query = mysqli_query($cnx, $sqlArr);
foreach ($query as $key => $v ){
if ($v['xid_arrival'] == 0) {?>
<tr>
<td>ARR</td>
<td><?=$v['arr_date'];?> </td>
<td><?=$v['atyp'];?> </td>
<td><?= $v['reg'];?> </td>
<td><?=$v['arr_cls'];?> </td>
<td><?=$v['adep'];?> </td>
<td><?= date('H:i', strtotime($v['eta']));?> </td>
<td onclick="openRow(this, <?= $v['id_flt'];?>)">+</td>
</tr>
<tr hidden id="<?= $v['id_flt'];?>">
<td colspan="6">hidden id <?= $v['id_flt'];?></td>
</tr>
<?php } else { ?>
<tr>
<td>DEP</td>
<td><?=$v['dep_date'];?> </td>
<td><?=$v['atyp'];?> </td>
<td><?= $v['reg'];?> </td>
<td><?=$v['dep_cls'];?> </td>
<td><?=$v['ades'];?> </td>
<td><?= date('H:i', strtotime($v['etd']));?> </td>
<td onclick="openRow(this, <?= $v['xid_arrival'];?>)">+</td>
</tr>
<tr hidden id="<?= $v['xid_arrival'];?>">
<td colspan="6">hidden xid <?= $v['xid_arrival'];?></td>
</tr>
<?php }?>
<?php } ?>

Answer 1

You need to create one column with departure or arrival date depending which is defined in a line and order by that column.
Something like this
SELECT
*,
CASE
WHEN eta > 0 THEN eta
WHEN etd > 0 THEN etd
END as sort_order
FROM flights
WHERE
arr_date = '$date' OR dep_date = '$date'
ORDER BY
sort_order ASC;
And remember to escape data you get as input to your SQL query to prevent SQL injection vulnerabilities.
And SELECT * is lazy coding. Select only columns you neeed.