How to make a select with the option correctly? - php

Question

What is the best way to return exactly the select option that the end user chose?
In my query for example when selecting the imoveis_tipo
Returns me all the data being HOUSES, APARTMENTS, TERRENOS;
How do I return only 1 purpose type?
If my question was not very clear, please comment here so I can adjust my question.
Here's an example showing what I'm trying to do, by selecting PURPOSE as SALE
PROPERTY TYPE as 2 BEDROOM APARTMENT
And the CITY as CAPÃO DA CANOA
Returns me all the records in the database and not just the ones I selected in the search.
This is my code showing the purpose, type and city:
<div class="col-md-12">
<label class="font-color-white font-weight-600 font-size-14 text-uppercase">Finalidade</label>
<select id="finalidade" name="finalidade" class="form-control" required>
<option value="0">
Selecione...
</option>
<?php
$sql5 = mysqli_query($link, "SELECT * FROM imoveis_finalidades WHERE status='S' ORDER BY nome");
while ($dados5 = mysqli_fetch_array($sql5)) {
?>
<option value='<?php echo $dados5['url'] ?>'>
<?php echo ($dados5['nome']); ?>
</option>
<?php
}
?>
</select>
</div>
<div class="col-md-12">
<label class="font-color-white font-weight-600 font-size-14 text-uppercase">Tipo de Imóvel</label>
<select id="tipo" name="tipo" class="form-control" required>
<option value="0">
Selecione...
</option>
<?php
$sql5 = mysqli_query($link, "SELECT * FROM imoveis_tipos WHERE status='S' ORDER BY nome ");
while ($dados5 = mysqli_fetch_array($sql5)) {
?>
<option value='<?php echo $dados5['url'] ?>'>
<?php echo ($dados5['nome']); ?>
</option>
<?php
}
?>
</select>
</div>
<div class="col-md-12">
<label class="font-color-white font-weight-600 font-size-14 text-uppercase">Cidade</label>
<select id="cidade" name="cidade" class="form-control" required>
<option value="0">
Selecione...
</option>
<?php
$sql6 = mysqli_query($link, "SELECT * FROM localidades_cidades WHERE status='S' ORDER BY nome");// or die (mysqli_error($link));
while ($dados6 = mysqli_fetch_array($sql6)) {
?>
<option value='<?php echo $dados6['url'] ?>'>
<?php echo ($dados6['nome']); ?>
</option>
<?php
}
?>
</select>
</div>