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im getting this weird error and i don't know what im doing wrong
it has something to do with this line:
$result = mysqli_query($connection,$query);
plex help me fix this
this is my code:
<?php
define("HOSTNAME", "localhost");
define("USERNAME", "root");
define("PASSWORD", "");
define("DATABASE", "courses");
$connection = mysqli_connect(HOSTNAME,USERNAME,PASSWORD,DATABASE);
if(isset($_POST['add_data'])) {
$name = $_POST['name'];
$description = $_POST['description'];
$duration = $_POST['duration'];
$price = $_POST['price'];
if($name == "" || empty($name)) {
header('location:index.php?message= you need to fill in your name');
} else {
$query = "insert into `courses` (`name,` `description`, `duration`, `price`) values
('$name', '$description', '$duration', '$price')";
$result = mysqli_query($connection,$query); ERROR line 25
if(!$result) {
die("query Failed".mysqli_error());
} else {
header('location:index.php?insert_msg= your data has been added');
}
}
}
?>
my index page:
https://pastebin.com/diNNpPWk
im trying to make a crud application but i'm unable to insert any data
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I'm trying to assign the value of $data['id'] to a variable like this:
$totalfor = $data['id'];
but this is not working, the value is not passing to $totalfor
If i echo $data['id'], it gives the right value which is 85
i need the value of $data['id'] to use it into a Select query
Anyone know the correct syntax to achieve this ?
Thanks
Here is the code:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test";
$jury = get_active_user('accountname');
$totalfor = $data['id'];
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT total AS total FROM votestepone WHERE votefor = '$totalfor' AND votedby= '$jury'";
$result = $conn->query($sql);
if ($result = mysqli_query($conn, $sql)) {
while ($row = mysqli_fetch_assoc($result)) {
$totalvote = $row["total"];
}
} else {
echo "0 results";
}
?>
<?php echo $totalvote; ?>
The error is : Undefined variable: totalvote
If i set
$totalfor = 85; --> it works
but i need to use the value coming from $data['id'];
I'm in a view page and $data['id'] is coming from:
$data = $this->view_data;
if I <?php echo $data['id']; ?> it show 85
mysqli_query returns false when there is an error not if there are no results. The error says $totalvote is undefined, not $totalfor so the query didn't find a single result.
var_dump($sql) and make sure the query is correct and it really does fetch a result row when run against your database.
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Closed 6 years ago.
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I am trying for user login and registration forms in Android. From past 5 days, I am trying it. I am not able to get it. Can anyone help me please? This is my code user_control.php. I am including the connection.php in user_control.php.
<? php
class user {
private $db;
private $connection;
/* The below one is the consttructor*/
function __construct() {
header('Content-Type: application/json'); /* used for including json format*/
require_once 'connection.php';
$this->db = new DB_Connection();
$this->connection = $this->db->get_connection();
}
public function does_user_exist($email,$password) {
$query = "Select * from userss where email ='$email' and password = '$password'";
$result = mysqli_query($this->connection,$query);
if(mysqli_num_rows($result) > 0){
$json['success'] = 'welcome'.$email;
echo json_encode($json);
mysqli_close($this->connection);
} else {
$query = " Insert into userss(email,password) values ('$email','$password')";
$is_inserted = mysqli_query($this->connection, $query);
if($is_inserted == 1) {
$json['success'] = 'Account created, welcome '.$email;
} else {
$json['error'] = 'Wrong password';
}
echo json_encode($json);
mysqli_close($this->connection);
}
}
}
$user = new user();
if(isset($_POST['email'],$_POST['password'])) {
$email = $_POST['email'];
$password = $_POST['password'];
if(!empty($email) && !empty($password)) {
$encrypted_password = md5($password);
$user -> does_user_exist($email,$encrypted_password);
} else {
echo json_encode("You must fill both fields");
}
}
While I am running with postman software by Chrome I am getting the error as I am getting syntax error:
unexpected 'header' (T_STRING) in http://localhost:80/opt/lampp/htdocs/user_control.php
Remove the space in your line 1. Should looks like:
<?php
Try to comment:
//header('Content-Type: application/json'); /* used for including json format*/
Source: https://stackoverflow.com/a/20620606/2381906
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Perhaps I'm missing something very obvious here.
My code doesn't seem to work below the 'GET BOOK ID' annotation if I don't close and reopen the connection.
While it does work, it doesn't seem to be an efficient way at all to do this, any suggestions?
$AddBook = $conn->prepare("CALL makeBooking((SELECT CustID FROM customer WHERE UserName = '$UserName'), ?, ?, ?, ?, now())");
$AddBook->bind_param('iiis',$PerfID, $NumAdults, $NumChilds, $ColTicket);
if ($AddBook->execute())
{
//----------------DEDUCT SEATS--------------//
$SeatDeduction = $conn->prepare("CALL deductSeats($TotalSeats,?)");
$SeatDeduction->bind_param('i',$PerfID);
$SeatDeduction->execute();
mysqli_close($conn);
require ('connect.php');
//-----------------GET BOOK ID--------------//
$getBookID = "CALL getBookByUserName('$UserName')";
$result2 = mysqli_query($conn, $getBookID);
$Output2 = mysqli_fetch_assoc($result2);
$BookID = $Output2['BookID'];
mysqli_close($conn);
require ('connect.php');
//-------------------SET COST---------------//
$setCost = "CALL setBookingPrice($BookID)";
mysqli_query($conn,$setCost);
mysqli_close($conn);
require ('connect.php');
//-------------------GET COST---------------//
$getCost = "CALL getCost($BookID)";
$result6 = mysqli_query($conn,$getCost);
$Output6 = mysqli_fetch_assoc($result6);
$Cost = $Output6['TotalCost'];
mysqli_close($conn);
require ('connect.php');
//---------------BOOKING CONFIRM------------//
$ShowRef = 'Booking Completed<p>Reference Number: <b>' . $BookID . '</b><p>';
$showCost = 'Total Cost: <b><u>£' . $Cost . '<u><b><br>';
$Confirm = $ShowRef.$showCost;
}
else
{
die(mysqli_error($conn));
}
mysqli_close($conn);
You don't have to keep including the connect.php file over and over.
Assuming you already included it somewhere at the top since you run $AddBook->execute()
See this updated code:
$AddBook = $conn->prepare("CALL makeBooking((SELECT CustID FROM customer WHERE UserName = '$UserName'), ?, ?, ?, ?, now())");
$AddBook->bind_param('iiis',$PerfID, $NumAdults, $NumChilds, $ColTicket);
if ($AddBook->execute())
{
//----------------DEDUCT SEATS--------------//
$SeatDeduction = $conn->prepare("CALL deductSeats($TotalSeats,?)");
$SeatDeduction->bind_param('i',$PerfID);
$SeatDeduction->execute();
$SeatDeduction->close();
$conn->next_result();
// mysqli_close($conn); // remove this
// require ('connect.php'); // remove this
//-----------------GET BOOK ID--------------//
$getBookID = "CALL getBookByUserName('$UserName')";
$result2 = mysqli_query($conn, $getBookID);
$Output2 = mysqli_fetch_assoc($result2);
$BookID = $Output2['BookID'];
// mysqli_close($conn); remove this
// require ('connect.php'); remove this
//-------------------SET COST---------------//
// ...
//-------------------GET COST---------------//
// ...
//---------------BOOKING CONFIRM------------//
// ...
}
else
{
die(mysqli_error($conn));
}
mysqli_close($conn);
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Closed 8 years ago.
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<form action = "index.php" method = "post">
username : <input type = "text" name = "uname" /><br>
password : <input type = "text" name = "pass" /><br>
submit : <input type = "submit" name = "submit" value = "submit" />
</form>
<?php
if(isset($_SESSION['id'])){echo $_SESSION['id'];}
if(isset($_POST['submit'])){
if ($_POST['submit'] == 'submit'){
$uname = $_POST['uname'];
$pass = $_POST['pass'];
$db = "davidedwardcakes";
$connect = mysql_connect('localhost', 'root', 'wtfiwwu');
$db_connect = mysql_selectdb($db, $connect);
if(!$db_connect){echo 'no';}
$query = "SELECT * FROM `users` WHERE uname ='$uname' AND pass = '$pass'";
$result = mysql_query($query, $connect);
if(mysql_num_rows($result) > 0){//echo 'index failed'; var_dump($result);}
while($row = mysql_fetch_array($result)){echo $row['uname']
. "<br>";
session_start();
echo 'peruse';
$_SESSION['id'] = $row['id'];}}
else{echo 'lol'; var_dump($query);}}
Whenever I want to login, i get the error:
string 'SELECT * FROM users WHERE uname ='brown' AND pass = 'kenji'' (length=61)
meaning that theres a problem with my $query. If I remove the $pass query from $query it works fine but doesn't when it is included. Can anybody help please.
Let me convert your code to MySQLi at least. MySQL is already deprecated.
<?php
/* ESTABLISH CONNECTION */
$connect=mysqli_connect("YourHost","YourUsername","YourPassword","YourDatabase"); /* REPLACE NECESSARY DATA */
if(mysqli_connect_errno()){
echo "Error".mysqli_connect_error();
}
/* REPLACE THE NECESSARY POST DATA BELOW AND PRACTICE ESCAPING STRINGS BEFORE USING IT INTO A QUERY TO AVOID SOME SQL INJECTIONS */
$uname=mysqli_real_escape_string($connect,$_POST['username']);
$pass=mysqli_real_escape_string($connect,$_POST['password']);
$query = "SELECT * FROM `users` WHERE uname ='$uname' AND pass ='$pass'";
$result = mysqli_query($connect,$query); /* EXECUTE QUERY */
if(mysqli_num_rows($result)==0){
echo 'login failed';
var_dump($result);
}
else {
while($row = mysqli_fetch_array($result)){
echo $row['uname'];
} /* END OF WHILE LOOP */
echo 'Successfully Logged-in.';
var_dump($query);
} /* END OF ELSE */
?>
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Closed 8 years ago.
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I got this error
Parse error: syntax error, unexpected '}' in C:\wamp\www\widget_corp\public
\create_subject.php on line 24
when I clicked on my "Creae Subject" button.
I have tried to fix it all day but really can't find what the problem is.
<?php require_once ("../includes/session.php"); ?>
<?php require_once ("../includes/db_connection.php"); ?>
<?php require_once ("../includes/functions.php"); ?>
<?php require_once ("../includes/validation_function.php"); ?>
<?php
if (isset($_POST['submit'])) {
// Process the form
$menu_name = mysql_prep($_POST["menu_name"]);
$position = (int) $_POST["position"];
$visible = (int) $_POST["visible"];
// Validations
$required_fields = array("menu_name", "position", "visible");
validate_presences($required_fields);
$fields_with_max_lengths = array("menu_name" => 30);
validate_max_lengths($fields_with_max_lengths);
if (!empty($errors)) {
$_SESSION["errors"] = $errors;
redirect_to("new_subject.php")
} <-------- THIS IS ROW 24! ----------->
$query = "INSERT INTO subjects (";
$query .= " menu_name, position, visible";
$query .= ") VALUES (";
$query .= " '{$menu_name}, {$position}, {$visible}";
$query .= ")";
$result = mysqli_query($connection, $query);
if ($result) {
// Success
$_SESSION["message"] = "Subject created!";
redirect_to("manage_content.php");
} else {
// Failure
$_SESSION["message"] = "Subject creation failed";
redirect_to("new_subject.php");
}
} else {
// This is probably a GET request
redirect_to("new_subject.php");
}
?>
<!-- Close database connection -->
<?php if (isset($connection)) { mysqli_close($connection); } ?>
Missing semicolon on the line above the brace.
redirect_to("new_subject.php")
A lot of times you have to look at the line above the one given in the error to see what the problem is.
you have missed semicolon in this line:
redirect_to("new_subject.php");
try this:
if (!empty($errors)) {
$_SESSION["errors"] = $errors;
redirect_to("new_subject.php");
}